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问题:
I am using the entries of a db to fill a row and a column in a table. But I cannot access the SQL returned data twice using mysqli_fetch_array() twice. This doesn't work:
//Copy the result $db_res = mysqli_query( $db_link, $sql ); $db_res2=$db_res; //Top row while ($row = mysqli_fetch_array( $db_res, MYSQL_ASSOC)) { echo "| ". $row['Title'] . " | "; } //leftmost column while ($row = mysqli_fetch_array( $db_res2, MYSQL_ASSOC)) { echo ""; echo "| ". $row['Title'] . " | "; ..... echo "
"; }
How can I apply mysqli_fetch_array twice on the same result?
回答1:
You should always separate data manipulations from output.
Select your data first:
$db_res = mysqli_query( $db_link, $sql ); $data = array(); while ($row = mysqli_fetch_assoc($db_res)) { $data[] = $row; }
Note that in the recent PHP versions you can use fetch_all() instead of the explicit loop:
$db_res = mysqli_query( $db_link, $sql ); $data = $db_res->fetch_all(MYSQLI_ASSOC);
Then use it as many times as you wish:
//Top row foreach ($data as $row) { echo "| ". $row['Title'] . " | "; } //leftmost column foreach ($data as $row) { echo ""; echo "| ". $row['Title'] . " | "; ..... echo "
"; }
回答2:
Yes. mysqli_fetch_array() moves the pointer forward each time you call it. You need mysqli_data_seek() to set the pointer back to the start and then call mysqli_fetch_array() again.
So before calling the function a second time, do:
mysqli_data_seek($db_res, 0);
回答3:
$squery = mysqli_query($con,"SELECT * FROM table"); while($s = mysqli_fetch_array($query)){ .... } // add this line mysqli_data_seek( $query, 0 ); while($r = mysqli_fetch_array($query)){ ... }
try it.....
