XSLT 2.0 if condition

问题:

Need help on XSLT 2.0 transformation.

Input xml :

<Employee> <Post>Manager</Post> </Employee> 

pseudo code :

if(Employee/Post = 'Manager') then Associate/High = 'Band' else Associate/Low = 'Band' 

Output xml :

<Associate> <High>Band</High> </Associate>  <Associate> <Low>Band</Low> </Associate> 

回答1:

Construct an element dynamically with xsl:element. Other than that, your pseudo code is already pretty accurate.

XSLT Stylesheet

<?xml version="1.0" encoding="UTF-8" ?> <xsl:transform xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="2.0">     <xsl:output method="xml" omit-xml-declaration="yes" encoding="UTF-8" indent="yes" />      <xsl:template match="Employee">       <Associate>           <xsl:element name="{if (Post = 'Manager') then 'High' else 'Low'}">               <xsl:value-of select="'Band'"/>           </xsl:element>       </Associate>     </xsl:template>  </xsl:transform> 

XML Output

<Associate>    <High>Band</High> </Associate> 

回答2:

I would use a template

<xsl:template match="Employee">   <Associate>     <xsl:apply-templates/>   </Associate> </xsl:template> 

and then

<xsl:template match="Employee/Post[. = 'Manager']">   <High>Band</High> </xsl:template>  <xsl:template match="Employee/Post[not(. = 'Manager')]">   <Low>Band</Low> </xsl:template> 

文章来源: XSLT 2.0 if condition