问题
Ok, maybe my brain is just shut off, but I can't get this to work.
Here's the complete code:
Page1.php:
<?php
$something = "hello";
include "Page2.php";
?>
Page2.php:
<?php
echo $something;
?>
Desired output (when navigating to Page1.php):
hello
The real output is blank. I have tried putting the global keyword everywhere, and nothing happens. Am I missing something?
回答1:
I cannot replicate this error, just tried this on my localhost and copied and pasted your code from here. I suspect you have some sort of syntax error.
Turn on error reports and see if you get any errors.
回答2:
I know this is a late answer, but I'm trying to do something similar. First of all, when you echo something you still have to put it in " ". Php will recognize it as a variable as long as you put the $.
Second, you're including page2.php in page1. Fantastic, but page2 does not recognize $something. Now, if you do it the other way, declare $something in page2, and then call it from page 1 after including it, it will run.
Modifying the variable would require something else...
回答3:
I think the output is coming in page2.php . Am i right? this is because you are echoing a unset variable in page2.php you need to change the following data in order to make it work. page1.php
<?php
include("page2.php");
echo $something;
?>
page2.php
<?php
$something="Hello";
?>
If you will use it and navigate the page 1.php then the output will be Hello
回答4:
I had a similar problem running on local (Windows) where the values of an array did not follow past the include within the same process.
After switching the include path from http://localhost/www/example.php to C:/www/example.php, it works fine now.
来源：https://stackoverflow.com/questions/4869512/php-global-variables-across-files