sys_call_table in linux kernel 2.6.18

Question

I am trying to set the sys exit call to a variable by

extern void *sys_call_table[];
real_sys_exit = sys_call_table[__NR_exit]

however, when I try to make, the console gives me the error

error: ‘__NR_exit’ undeclared (first use in this function) 

Any tips would be appreciated :) Thank you

Answer 1

Since you are in kernel 2.6.x , sys_call_table isnt exported any more. If you want to avoid the compilation error try this include

#include<linux/unistd.h>

however, It will not work. So the work around to "play" with the sys_call_table is to find the address of sys_call_table in SystemXXXX.map (located at /boot) with this command:

grep sys_call System.map-2.6.X -i

this will give the addres, then this code should allow you to modify the table:

unsigned long *sys_call_table; 
sys_call_table = (unsigned long *) simple_strtoul("0xc0318500",NULL,16); 


original_mkdir = sys_call_table[__NR_mkdir];
sys_call_table[__NR_mkdir] = mkdir_modificado;

Hope it works for you, I have just tested it under kernel 2.6.24, so should work for 2.6.18

also check here, Its a very good http://commons.oreilly.com/wiki/index.php/Network_Security_Tools/Modifying_and_Hacking_Security_Tools/Fun_with_Linux_Kernel_Modules

Answer 2

If you haven't included the file syscall.h, you should do that ahead of the reference to __NR_exit. For example,

#include <syscall.h>
#include <stdio.h>

int main()
{
    printf("%d\n", __NR_exit);
    return 0;
}

which returns:

$ cc t.c
$ ./a.out 
60

Some other observations:

1. If you've already included the file, the usual reasons __NR_exit wouldn't be defined are that the definition was being ignored due to conditional compilation (#ifdef or #ifndef at work somewhere) or because it's being removed elsewhere through a #undef.

2. If you're writing the code for kernel space, you have a completely different set of headers to use. LXR (http://lxr.linux.no/linux) searchable, browsable archive of the kernel source is a helpful resource.