问题
I have this code
$(document).ready(function(){
$('.selector').click(function(){
obj = $(this);
obj.replaceWith('<div class="size">whats up man ??!</div>');
alert(obj.html());
});
});
I want to get the new content of 'obj' that has been 'replaceWith'
but,
I get the old content instead ...
how do I get the actual content of 'obj' ???
my intention is to access the new 'obj'
$('.selector').click(function(){
var obj = $(this),
repl = $('<div class="size">whats up man ??! <span class="medium"></span></div>');
obj.replaceWith(repl);
alert(obj.find('span').attr('class')); //this will print 'undefined'
});
I want to print the class name of the 'span' which is 'medium'
回答1:
Your updated method is the correct one, just needs a tweak like this:
$('.selector').click(function(){
var obj = $(this),
repl = $('<div class="size">whats up man ??! <span class="medium"></span></div>');
obj.replaceWith(repl);
alert(repl.find('span').attr('class'));
});
You can test it out here. The important change is the repl.find()
to look in the new element instead of the old one.
回答2:
why do you want to do that? you know what you replaced it with....
$(document).ready(function(){
$('.selector').click(function(){
var obj = $(this);
var replacement = $('<div class="size">whats up man ??!</div>');
obj.replaceWith(replacement);
alert(replacement.html());
});
});
来源:https://stackoverflow.com/questions/3573521/how-to-get-actual-content-of-an-object-after-being-replacewithsomething-in-j