问题
Instead of encapsulating my entire code in a try{} except{} block, is there someway of catching exceptions globally?
Basically I am looking for a way to have a global exception handler which will handle all unhandled exceptions in the my python application written for google app engine
回答1:
If you're using the webapp framework, you should already be defining a subclass of RequestHandler that serves as a base class, with all your app's handlers extending that. You can simply override handle_exception, which serves as a global exception handler for any uncaught exceptions.
The default implementation calls self.error(500), logs the exception, and if debug is on, outputs a stacktrace.
If you're using another framework, you could write a piece of WSGI middleware that calls the wrapped WSGI app, and catches any thrown exceptions, dealing with them as you wish.
回答2:
Well, at the most basic level you could wrap all of your handler scripts referenced by app.yaml in a giant try-except block.
If you are using the webapp framework, consider overriding handle_exception() for each of your request handlers. If you want all of your request handlers to have some basic exception handling that you specify, you could a request handler which implements this method and then derive all of your handlers from it.
回答3:
You application probably has a main() function, put the try/except in that function, and it'll catch everything from your application.
来源：https://stackoverflow.com/questions/3154900/global-exception-handling-in-google-app-engine