R: Generic flattening of JSON to data.frame

南笙酒味 提交于 2019-11-30 02:16:27
shhhhimhuntingrabbits

Hi @Sim I had cause to reflect on your problem yesterday define:

flatten<-function(x) {
    dumnames<-unlist(getnames(x,T))
    dumnames<-gsub("(*.)\\.1","\\1",dumnames)
    repeat {
        x <- do.call(.Primitive("c"), x)
        if(!any(vapply(x, is.list, logical(1)))){
           names(x)<-dumnames
           return(x)
        }
    }
}
getnames<-function(x,recursive){

    nametree <- function(x, parent_name, depth) {
        if (length(x) == 0) 
            return(character(0))
        x_names <- names(x)
        if (is.null(x_names)){ 
            x_names <- seq_along(x)
            x_names <- paste(parent_name, x_names, sep = "")
        }else{ 
            x_names[x_names==""] <- seq_along(x)[x_names==""]
            x_names <- paste(parent_name, x_names, sep = "")
        }
        if (!is.list(x) || (!recursive && depth >= 1L)) 
            return(x_names)
        x_names <- paste(x_names, ".", sep = "")
        lapply(seq_len(length(x)), function(i) nametree(x[[i]], 
            x_names[i], depth + 1L))
    }
    nametree(x, "", 0L)
}

(getnames is adapted from AnnotationDbi:::make.name.tree)

(flatten is adapted from discussion here How to flatten a list to a list without coercion?)

as a simple example

my_data<-list(x=list(1,list(1,2,y='e'),3))

> my_data[['x']][[2]][['y']]
[1] "e"

> out<-flatten(my_data)
> out
$x.1
[1] 1

$x.2.1
[1] 1

$x.2.2
[1] 2

$x.2.y
[1] "e"

$x.3
[1] 3

> out[['x.2.y']]
[1] "e"

so the result is a flattened list with roughly the naming structure you suggest. Coercion is avoided also which is a plus.

A more complicated example

library(RJSONIO)
library(RCurl)
json.data<-getURL("http://www.reddit.com/r/leagueoflegends/.json")
dumdata<-fromJSON(json.data)
out<-flatten(dumdata)

UPDATE

naive way to remove trailing .1

my_data<-list(x=list(1,list(1,2,y='e'),3))
gsub("(*.)\\.1","\\1",unlist(getnames(my_data,T)))

> gsub("(*.)\\.1","\\1",unlist(getnames(my_data,T)))
[1] "x.1"   "x.2.1" "x.2.2" "x.2.y" "x.3"  

R has two packages for dealing with JSON input: rjson and RJSONIO. If I understand correctly what you mean by "collection of non-cyclical homogeneous or heterogeneous data structures", I think either of these packages will import that sort of structure as a list.

You can then flatten that list (into a vector) using the unlist function.

If the list is suitably structured (a non-nested list where each element is the same length) then as.data.frame prvoides an alternative to convert the list to be a data frame.

An example:

(my_data <- list(x = list('1' = 1, '2' = list(y = 2))))
unlist(my_data)

The jsonlite package is a fork of RJSONIO specifically designed to make conversion between JSON and data frames easier. You don't provide any example json data, but I think this might be what you are looking for. Have a look at this blog post or the vignette.

Great answer with the flatten and getnames functions. Took a few minutes to figure out all the options needed to get from a vector of JSON strings to a data.frame, so I thought I'd record that here. Suppose jsonvec is a vector of JSON strings. The following builds a data.frame (data.table) where there is one row per string, and each column corresponds to a different possible leaf node of the JSON tree. Any string missing a particular leaf node is filled with NA.

library(data.table)
library(jsonlite)
parsed = lapply(jsonvec, fromJSON, simplifyVector=FALSE)
flattened = lapply(parsed, flatten) #using flatten from accepted answer
d = rbindlist(flattened, fill=TRUE)
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