Print stdout in Python without shell escape sequences

Question

I'm using sh to run git commands inside a Python script.

In [1]: from sh import git

In [2]: s = git("log", "-1", pretty="format:%h %s")

In [3]: print s
4f14a66 basic debug page

This seems to work as expected. However, using this in a Django template gives [?1h= 4f14a66 basic debug page[m [K[?1l>. I tried to see what characters were in this string using repr(), to no avail:

In [4]: print repr(s)
4f14a66 basic debug page

It turns out commands in sh return a RunningCommand that has a .stdout attribute:

In [5]: type(s)
Out[5]: sh.RunningCommand

In [7]: s.stdout
Out[7]: '\x1b[?1h\x1b=\r4f14a66 basic debug page\x1b[m\r\n\r\x1b[K\x1b[?1l\x1b>'

How do I get "4f14a66 basic debug page" i.e. the string without the escapes? Running the command from Bash is fine:

$ git log -1 --pretty="format:%h %s"
4f14a66 basic debug page

Answer 1

s.stdout in the REPL will not print it but display its repr(). Use print s.stdout to get what you are looking for.

If you do not want any escape codes consider executing it using subprocess.call() - with stdout not being a tty most programs do not output any escape sequences.

Answer 2

According to this GitHub issue, correct solution to the problem is to use _tty_out=False:

>>> str(git('show', format='%cN', s=True))
'\x1b[?1h\x1b=\rHonza Javorek\x1b[m\r\n\r\x1b[K\x1b[?1l\x1b>'

>>> str(git('show', format='%cN', s=True, _tty_out=False))
'Honza Javorek\n'

This is also solution for my duplicate question: Using sh, git show returns special characters - how to get plain output?