Can I check if Bootstrap Modal Shown / Hidden?

Question

Can I check if Bootstrap Modal currently Shown / Hidden Programatically?

Like bool a = if("#myModal").shown(); ?

I need true/false

Answer 1

alert($('#myModal').hasClass('in'));

It will return true if modal is open

Answer 2

The best method is given in the docs

$('#myModal').on('shown.bs.modal', function () {
  // will only come inside after the modal is shown
});

for more info refer http://getbootstrap.com/javascript/#modals

Answer 3

its an old question but anyway heres something i used incase someone was looking for the same thing

if (!$('#myModal').is(':visible')) {
    // if modal is not shown/visible then do something
}

Answer 4

When modal hide? we check like this :

$('.yourmodal').on('hidden.bs.modal', function () {
    // do something here
})

Answer 5

Use hasClass('in'). It will return true if modal is in OPEN state.

E.g:

if($('.modal').hasClass('in')){
   //Do something here
}

Answer 6

In offical way:

> ($("element").data('bs.modal') || {})._isShown    // Bootstrap 4
> ($("element").data('bs.modal') || {}).isShown     // Bootstrap <= 3

{} is used to avoid the case that modal is not opened yet (it return undefined). You can also assign it equal {isShown: false} to keep it's more make sense.

Answer 7

if($('.modal').hasClass('in')) {
    alert($('.modal .in').attr('id')); //ID of the opened modal
} else {
    alert("No pop-up opened");
}

Answer 8

With Bootstrap 4:

if ($('#myModal').hasClass('show')) {
    alert("Modal is visible")
}

Answer 9

For me this works

 
if($("#myModal").css("display") !='none' && $("#myModal").css("visibility") != 'hidden')

alert("modal shown");