问题
I am using ffmpeg to get some jpg from my video at a specific rate (one screenshot every 5 seconds) with this command :
ffmpeg -i source -f image2 -r 1/5 %d.jpg
This works and give me sequential filenames :
1.jpg
2.jpg
3.jpg
4.jpg
What if I need to know at which time those screenshots have been taken ? Something like a timestamp :
00:00:00.0000.jpg
00:00:05.0000.jpg
00:00:10.0000.jpg
00:00:15.0000.jpg
or the number of seconds :
0.jpg
5.jpg
10.jpg
15.jpg
I tried again with the new -frame_pts option :
ffmpeg -i source -f image2 -r 1/5 -frame_pts 1 %d.jpg
I got similar sequential filenames, but now they are starting from zero :
0.jpg
1.jpg
2.jpg
3.jpg
回答1:
Use
ffmpeg -i source -vf fps=1,select='not(mod(t,5))' -vsync 0 -frame_pts 1 z%d.jpg
frame_pts will assign a serial number to the image name, where the number represents the frame position as per the output timebase. So the calculated time position is frame # x timebase. The timebase is the reciprocal of the output framerate e.g. for a 12 fps stream, timebase is 1/12. So output file image212 represents a time of 212 x 1/12 = 17.67s
To represent seconds, you need to generate a 1 fps stream and then pick every 5th frame, to get a frame from every 5th second. The vsync 0 is added to prevent ffmpeg from duplicating frames to generate a constant frame rate stream.
来源：https://stackoverflow.com/questions/50099869/ffmpeg-output-images-filename-with-time-position