问题
How to extract the name and url?
quotes_spiders.py
import scrapy
import json
class QuotesSpider(scrapy.Spider):
name = "quotes"
start_urls = ["http://www.lazada.com.my/shop-power-banks2/?price=1572-1572"]
def parse(self, response):
data = json.loads(response.xpath('//script[@type="application/ld+json"]//text()').extract_first())
//how to extract the name and url?
yield data
Data to Extract
<script type="application/ld+json">{"@context":"https://schema.org","@type":"ItemList","itemListElement":[{"@type":"Product","image":"http://my-live-02.slatic.net/p/2/test-product-0601-7378-08684315-8be741b9107b9ace2f2fe68d9c9fd61a-webp-catalog_233.jpg","name":"test product 0601","offers":{"@type":"Offer","availability":"https://schema.org/InStock","price":"99999.00","priceCurrency":"RM"},"url":"http://www.lazada.com.my/test-product-0601-51348680.html?ff=1"}]}</script>
回答1:
This line of code returns a dictionary with the data you want:
data = json.loads(response.xpath('//script[@type="application/ld+json"]//text()').extract_first())
All you need to do is to access it like:
name = data['itemListElement'][0]['name']
url = data['itemListElement'][0]['url']
Given that the microdata contains a list you will need to check you are referring to the correct product in the list.
回答2:
A really easy solution for this would be to use https://github.com/scrapinghub/extruct. It handles all the hard parts of extracting structured data.
来源:https://stackoverflow.com/questions/44939247/scrapy-extract-ldjson