Convert Soap XML response to Object

问题

i'm new to working with SOAP API's

I have a soap response from an API

<soapenv:Envelope xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/">
<soapenv:Body>
<LoginResponse xmlns="http://test.org/ADMail_Service">
<LoginResult>
<ErrorMessage>Successful login</ErrorMessage>
<Status>true</Status>
</LoginResult>
</LoginResponse>
</soapenv:Body>
</soapenv:Envelope>

I'm trying to transform this into an object.

From reading articles online I'm trying to use JAXB to do this, but my object is empty.

Here's the code for reading the response. I wrote the response to an xml file for test purposes:

try {
    XMLInputFactory xif = XMLInputFactory.newFactory();
    XMLStreamReader xsr = xif.createXMLStreamReader(new FileReader("input.xml"));
    xsr.nextTag(); // Advance to Envelope tag

    xsr.nextTag(); // Advance to Body tag
    xsr.nextTag();
    xsr.nextTag();


    JAXBContext jc = JAXBContext.newInstance(LoginResult.class);
    Unmarshaller unmarshaller = jc.createUnmarshaller();
    JAXBElement<LoginResult> je = unmarshaller.unmarshal(xsr, LoginResult.class);

    System.out.println(je.getName());
    System.out.println(je.getValue());
} catch (XMLStreamException e) {
    e.printStackTrace();
} catch (JAXBException e) {
    e.printStackTrace();
} catch (FileNotFoundException e) {
    e.printStackTrace();
}

The LoginResult class:

public class LoginResult {
    private String errorMessage;
    private String status;

    public String getErrorMessage() {
        return errorMessage;
    }

    public void setErrorMessage(String errorMessage) {
        this.errorMessage = errorMessage;
    }

    public String getStatus() {
        return status;
    }

    public void setStatus(String status) {
        this.status = status;
    }
}

Thanks in advance!

回答1:

you can use this code to retrieve a POJO, and also add an @XmlRootElement as header to your POJO.

(I did'nt test the code below)

XMLInputFactory xif = XMLInputFactory.newFactory();
        XMLStreamReader xsr = xif.createXMLStreamReader(new FileReader("input.xml"));
        xsr.nextTag(); // Advance to Envelope tag

        xsr.nextTag(); // Advance to Body tag
        xsr.nextTag();
        xsr.nextTag();

        Transformer transformer = TransformerFactory.newInstance().newTransformer();
        StringWriter stringWriter = new StringWriter();
        transformer.transform(new StAXSource(xsr), new StreamResult(stringWriter));
        StringReader sr = new StringReader(stringWriter.toString());
        JAXBContext jaxbContext = JAXBContext.newInstance(LoginResult.class);
        Unmarshaller unmarshaller = jaxbContext.createUnmarshaller();
        LoginResult loginResult = (LoginResult) unmarshaller.unmarshal(sr);

EDIT :

I found a solution for you:

    @XmlRootElement(name = "LoginResult", namespace = "http://test.org/ADMail_Service")
@XmlAccessorType(XmlAccessType.FIELD)
public class LoginResult {
    @XmlElement(name = "ErrorMessage", namespace = "http://test.org/ADMail_Service")
    private String errorMessage;
    @XmlElement(name = "Status", namespace = "http://test.org/ADMail_Service")
    private String status;

    public String getErrorMessage() {
        return errorMessage;
    }

    public void setErrorMessage(String errorMessage) {
        this.errorMessage = errorMessage;
    }

    public String getStatus() {
        return status;
    }

    public void setStatus(String status) {
        this.status = status;
    }
}


public static void main(String[] args) {
        try {
            XMLInputFactory xif = XMLInputFactory.newFactory();
            XMLStreamReader xsr = xif.createXMLStreamReader(new FileReader("input.xml"));
            xsr.nextTag(); // Advance to Envelope tag

            xsr.nextTag(); // Advance to Body tag
            xsr.nextTag();
            xsr.nextTag();


            JAXBContext jc = JAXBContext.newInstance(LoginResult.class);
            Unmarshaller unmarshaller = jc.createUnmarshaller();
            JAXBElement<LoginResult> je = unmarshaller.unmarshal(xsr, LoginResult.class);

            System.out.println(je.getName());
            System.out.println(je.getValue());
            System.out.println(je.getValue().getErrorMessage());
        } catch (XMLStreamException e) {
            e.printStackTrace();
        } catch (JAXBException e) {
            e.printStackTrace();
        } catch (FileNotFoundException e) {
            e.printStackTrace();
        }

    }

回答2:

IMO, you should consider using tools to handle SOAP messages instead of doing it on your own.

Examples :

• Java EE 5 Tutorial : Creating a Simple Web Service and Client with JAX-WS
• Spring Boot : Consuming a SOAP message

---

EDIT

There's a few things to say about your comment so I'll put my answer here.

First,

I have nothing to do with the API, all I do is make a POST request...

You have nothing to do with the API but you make a POST request to the API. I think this is a figure of speech, right ?...

and there's no wsdl....

You can almost always get the WSDL of a SOAP webservice with this little trick. Just add ?wsdl at the end of the SOAP webservice URL.

Example :

Here's the URL of a SOAP webservice on the web (a real one) : http://www.webservicex.com/stockquote.asmx

You can get its WSDL like this : http://www.webservicex.com/stockquote.asmx?wsdl

So the only option is to parse the response

IMO, there's almost always more than one solution to a problem in software development.

来源：https://stackoverflow.com/questions/61514461/parsing-non-valid-soap-1-1-message-with-java