函数分类
HIVE CLI命令
显示当前会话有多少函数可用 SHOW FUNCTIONS;
显示函数的描写叙述信息 DESC FUNCTION concat;
显示函数的扩展描写叙述信息 DESC FUNCTION EXTENDED concat;
简单函数
函数的计算粒度为单条记录。
关系运算
数学运算
逻辑运算
数值计算
类型转换
日期函数
条件函数
字符串函数
统计函数
聚合函数
函数处理的数据粒度为多条记录。
sum()—求和
count()—求数据量
avg()—求平均直
distinct—求不同值数
min—求最小值
max—求最人值
集合函数
复合类型构建
复杂类型訪问
复杂类型长度
特殊函数
窗体函数
应用场景
用于分区排序
动态Group By
Top N
累计计算
层次查询
Windowing functions
lead lag FIRST_VALUE LAST_VALUE
分析函数
Analytics functions
RANK ROW_NUMBER DENSE_RANK CUME_DIST PERCENT_RANK NTILE
混合函数
java_method(class,method [,arg1 [,arg2]) reflect(class,method [,arg1 [,arg2..]]) hash(a1 [,a2...])
UDTF
lateralView: LATERAL VIEW udtf(expression) tableAlias AS columnAlias (',' columnAlias)* fromClause: FROM baseTable (lateralView)*
ateral view用于和split, explode等UDTF一起使用,它可以将一行数据拆成多行数据,在此基础上可以对拆分后的数据进行聚合。lateral view首先为原始表的每行调用UDTF,UTDF会把一行拆分成一或者多行。lateral view再把结果组合。产生一个支持别名表的虚拟表。
经常使用函数Demo:
create table employee( id string, money double, type string ) row format delimited fields terminated by '\t' lines terminated by '\n' stored as textfile; load data local inpath '/liguodong/hive/data' into table employee; select * from employee; 优先级依次为NOT AND OR select id,money from employee where (id='1001' or id='1002') and money='100';
cast类型转换
select cast(1.5 as int);
if推断
if(con,'',''); hive (default)> select if(2>1,'YES','NO'); YES
case when con then '' when con then '' else '' end (''里面类型要一样) select case when id='1001' then 'v1001' when id='1002' then 'v1002' else 'v1003' end from employee;
get_json_object
get_json_object(json 解析函数,用来处理json,必须是json格式) select get_json_object('{"name":"jack","age":"20"}','$.name');
URL解析函数
parse_url(string urlString, string partToExtract [, string keyToExtract]) select parse_url('http://facebook.com/path1/p.php?k1=v1&k2=v2#Ref1', 'HOST') from employee limit 1;
字符串连接函数: concat
语法: concat(string A, string B…)
返回值: string
说明:返回输入字符串连接后的结果,支持随意个输入字符串
举例:
hive> select concat('abc','def’,'gh') from lxw_dual; abcdefgh
带分隔符字符串连接函数: concat_ws
语法: concat_ws(string SEP, string A, string B…)
返回值: string
说明:返回输入字符串连接后的结果, SEP 表示各个字符串间的分隔符
concat_ws(string SEP, array<string>) 举例: hive> select concat_ws(',','abc','def','gh') from lxw_dual; abc,def,gh
列出该字段全部不反复的值,相当于去重 collect_set(id) //返回的是数组 列出该字段全部的值。列出来不去重 collect_list(id) //返回的是数组 select collect_set(id) from taborder;
求和 sum(money) 统计列数 count(*) select sum(num),count(*) from taborder;
窗体函数
first_value(第一行值) first_value(money) over (partition by id order by money) select ch,num,first_value(num) over (partition by ch order by num) from taborder;
rows between 1 preceding and 1 following (当前行以及当前行的前一行与后一行) hive (liguodong)> select ch,num,first_value(num) over (partition by ch order by num ROWS BETWEEN 2 PRECEDING AND CURRENT ROW) from taborder;
last_value 最后一行值 hive (liguodong)> select ch,num,last_value(num) over (partition by ch) from taborder;
lead 去当前行后面的第二行的值 lead(money,2) over (order by money) lag 去当前行前面的第二行的值 lag(money,2) over (order by money) ``` ``` select ch, num, lead(num,2) over (order by num) from taborder;
select ch, num, lag(num,2) over (order by num) from taborder;
rank排名
rank() over(partition by id order by money)
select ch, num, rank() over(partition by ch order by num) as rank from taborder;
select ch, num, dense_rank() over(partition by ch order by num) as dense_rank from taborder;
cume_dist
cume_dist (同样值的最大行号/行数) cume_dist() over (partition by id order by money) percent_rank (同样值的最小行号-1)/(行数-1) 第一个总是从0開始 percent_rank() over (partition by id order by money) select ch,num,cume_dist() over (partition by ch order by num) as cume_dist, percent_rank() over (partition by ch order by num) as percent_rank from taborder;
ntile分片 ntile(2) over (order by money desc) 分两份 select ch,num,ntile(2) over (order by num desc) from taborder;
混合函数
select id,java_method("java.lang,Math","sqrt",cast(id as double)) as sqrt from hiveTest;
UDTF
select id,adid from employee lateral view explode(split(type,'B')) tt as adid; explode 把一列转成多行 hive (liguodong)> select id,adid > from hiveDemo > lateral view explode(split(str,',')) tt as adid;
正則表達式
使用正則表達式的函数 regexp_replace(string subject A,string B,string C)
regexp_extract(string subject,string pattern,int index)
hive> select regexp_replace('foobar', 'oo|ar', '') from lxw_dual; fb hive> select regexp_replace('979|7.10.80|8684', '.*\\|(.*)',1) from hiveDemo limit 1;
hive> select regexp_replace('979|7.10.80|8684', '(.*?)\\|(.*)',1) from hiveDemo limit 1;
来源:https://www.cnblogs.com/ljbguanli/p/7354393.html