CompletableFuture chaining results

假如想象 提交于 2020-02-02 02:36:26

问题


I am trying to chain the calls/results of the methods to the next call. I get compile time error methodE because if am not able to get the reference of objB from the previous call.

How can I pass the result of the previous call to the next chain? Have I completely misunderstood the process?

Object objC = CompletableFuture.supplyAsync(() -> service.methodA(obj, width, height))
    .thenApply(objA -> {
    try {
        return service.methodB(objA);
    } catch (Exception e) {
        throw new CompletionException(e);
    }
})
   .thenApply(objA -> service.methodC(objA))
   .thenApply(objA -> {
   try {
       return service.methodD(objA); // this returns new objB how do I get it and pass to next chaining call 
       } catch (Exception e) {
           throw new CompletionException(e);
       }
    })
    .thenApply((objA, objB) -> {
       return service.methodE(objA, objB); // compilation error 
  })
 .get();

回答1:


You could store intermediate CompletableFuture in a variable and then use thenCombine:

CompletableFuture<ClassA> futureA = CompletableFuture.supplyAsync(...)
    .thenApply(...)
    .thenApply(...);

CompletableFuture<ClassB> futureB = futureA.thenApply(...);

CompletableFuture<ClassC> futureC = futureA.thenCombine(futureB, service::methodE);

objC = futureC.join();


来源:https://stackoverflow.com/questions/37265253/completablefuture-chaining-results

易学教程内所有资源均来自网络或用户发布的内容,如有违反法律规定的内容欢迎反馈
该文章没有解决你所遇到的问题?点击提问,说说你的问题,让更多的人一起探讨吧!