How to manipulate arrays. Find the average. Beginner Java

ε祈祈猫儿з 提交于 2019-11-27 14:11:06

Using an enhanced for would be even nicer:

int sum = 0;
for (int d : data) sum += d;

Another thing that will probably give you a big surprise is the wrong result that you will obtain from

double average = sum / data.length;

Reason: on the right-hand side you have integer division and Java will not automatically promote it to floating-point division. It will calculate the integer quotient of sum/data.length and only then promote that integer to a double. A solution would be

double average = 1.0d * sum / data.length;

This will force the dividend into a double, which will automatically propagate to the divisor.

-while(int i=0; i < data.length; i++) 
+for(int i=0; i < data.length; i++) 

The Java 8 streaming api offers an elegant alternative:

public static void main(String[] args) {
    double avg = Arrays.stream(new int[]{1,3,2,5,8}).average().getAsDouble();

    System.out.println("avg: " + avg);
}

Try this way

public void average(int[] data) {  
    int sum = 0;
    double average;

    for(int i=0; i < data.length; i++){
        sum = sum + data[i];
    }
    average = (double)sum/data.length;
    System.out.println("Average value of array element is " + average);    
}

if you need to return average value you need to use double key word Instead of the void key word and need to return value return average.

public double average(int[] data) {  
    int sum = 0;
    double average;

    for(int i=0; i < data.length; i++){
        sum = sum + data[i];
    }
    average = (double)sum/data.length;
    return average;    
}

Best way to find the average of some numbers is trying Classes ......

public static void main(String[] args) {
    average(1,2,5,4);

}

public static void average(int...numbers){
    int total = 0;
    for(int x: numbers){
        total+=x;
    }
    System.out.println("Average is: "+(double)total/numbers.length);

}

Well, to calculate the average of an array, you can consider using for loop instead of while loop.

So as per your question let me assume an array as arrNumbers ( here i'm considering the same array elements as in your question )

int arrNumbers[] = new int[]{1, 3, 2, 5, 8};
int sum = 0;

for(int a = 0; a < arrNumbers.length; a++)
{
   sum = sum + arrNumbers[a];
}

double average = sum / arrNumbers.length;

System.out.println("Average is: " + average);

You can use scanner class as well. It's left to you.

Couple of problems:

The while should be a for You are not returning a value but you have declared a return type of double

double average = sum / data.length;;

sum and data.length are both ints so the division will return an int - check your types

double semi-colon, probably won't break it, just looks odd.

Kastriot Rexhepi

If we want to add numbers of an Array and find the average of them follow this easy way! .....

public class Array {

    public static void main(String[] args) {

        int[]array = {1,3,5,7,9,6,3};
        int i=0;
        int sum=0;
        double average=0;
        for( i=0;i<array.length;i++){
            System.out.println(array[i]);
            sum=sum+array[i];
        }
        System.out.println("sum is:"+sum);
        System.out.println("average is: "+(double)sum/vargu.length);



    }

}
易学教程内所有资源均来自网络或用户发布的内容,如有违反法律规定的内容欢迎反馈
该文章没有解决你所遇到的问题?点击提问,说说你的问题,让更多的人一起探讨吧!