问题
I am using an Informix database. I want to get the difference between two dates, and the data type of return value must be an integer. The SQL looks like:
select (today - to_date('20121201','%Y%m%d')) from your_table_name
However, when I execute the SQL it returns 45 and certainly the computed value is not the integer type. What's the date type of the value? How can I cast the value to integer?
回答1:
The TO_DATE function is an Oracle import, and returns an Oracle DATE type in Oracle (hence the name), but the Oracle DATE type corresponds to an Informix DATETIME type. So, the Informix implementation of the TO_DATE() function returns a DATETIME type.
Problem
SELECT TODAY AS TODAY,
TO_DATE('20121201', '%Y%m%d') AS raw_to_date,
(TODAY - TO_DATE('20121201','%Y%m%d')) AS raw_difference
FROM sysmaster:informix.sysdual;
today raw_to_date raw_difference
DATE DATETIME YEAR TO FRACTION(5) INTERVAL DAY(8) TO DAY
2013-01-16 2012-12-01 00:00:00.00000 46
Solution
The solution for your expression is to apply the DATE function to the output of TO_DATE, or cast it to type DATE.
SELECT DATE(TO_DATE('20121201', '%Y%m%d')) AS date_to_date,
CAST(TO_DATE('20121201', '%Y%m%d') AS DATE) AS cast_to_date,
TO_DATE('20121201', '%Y%m%d')::DATE AS colon_to_date,
(TODAY - DATE(TO_DATE('20121201','%Y%m%d'))) AS date_difference
FROM sysmaster:informix.sysdual;
date_to_date cast_to_date colon_to_date date_difference
DATE DATE DATE INTEGER
2012-12-01 2012-12-01 2012-12-01 46
回答2:
The difference between two dates should be an integer. You should only get an INTERVAL
when computing the difference between DATETIME
values.
I don't have an Informix instance handy right now, but I suspect the use of the to_date()
function is resulting in DATETIME
math.
I can see you've come up with a solution, but try the following, which would be a lot simpler:
SELECT today - TO_DATE('20121201', '%Y%m%d')::DATE AS td FROM tb_dis_controll
来源:https://stackoverflow.com/questions/14331328/how-to-calculate-the-difference-between-two-dates-with-a-return-value-type-of-in