Oracle - unique Listagg values

问题

I am new to using Listagg. The following script works in respect of it gives me a list of values but, the list duplicates the values.

Is it possible to use Listagg to return only a unique list of values.

I am using oracle 10g.

select distinct ds.catnr,ds.planqty, ds.ordnr, ds.posnr, ds.segnr, 
listagg(case when not li.paco is null then (select unique max(li1.paco) from leos_item li1 where li.av_part_no = li1.av_part_no) end, ', ') within group (order by pd.part_no) inq_no
from oes_delsegview ds, oes_address ad, oes_opos op, oes_nrbom nr, scm_prodtyp sp, leos_item li, part_description pd
where ds.delnr = ad.key
and ad.adr = ds.deladr
and ds.pos_o_status not in ('9', 'D')
and ds.pos_c_status not in ('9', 'D')
and ds.seg_o_status not in ('9', 'D')
and ds.seg_c_status not in ('9', 'D')
and ds.cunr in ('W31170','W31172')
and ds.pos_type != 'RC'
and ds.ordnr = op.ordnr
and ds.posnr = op.posnr
and ds.catnr = pd.catnr
and ds.prodtyp = pd.prodtyp
and ds.packtyp = pd.packtyp
and ds.catnr = nr.p_catnr (+)
and ds.prodtyp = nr.p_prodtyp (+)
and ds.packtyp = nr.p_packtyp (+)
and nr.c_prodtyp = sp.prodtyp (+) 
and sp.prodgrp (+) = 'COMP'
and substr(nr.c_prodtyp,1,2) not in ('MT','LF')
and nr.c_catnr = li.catnr (+)
and nr.c_prodtyp = li.prodtyp (+)
and nr.c_packtyp = li.packtyp (+)
and pd.catnr = '9780007938797'
group by ds.catnr,ds.planqty, ds.ordnr, ds.posnr, ds.segnr

The result of my Listagg is:

14/061127-12, 14/061127-16, 14/061127-16, 14/061127-16, 14/061127-16, 14/061127-16, 14/061127-16, 14/061127-16, 14/061127-16, 14/061127-16, 14/061127-16, 14/061127-16, 14/061127-16, 14/061127-16, 14/061127-16, 14/061127-16, 14/061127-16, 14/061127-16, 14/061127-16, 14/061127-16, 14/061127-16

What I would like to see is:

14/061127-12, 14/061127-16

Any help would be much appreciated.

回答1:

I removed the first distinct since your already group by all fields in your Select query, and replaced the case when with a select query:

select ds.catnr,ds.planqty, ds.ordnr, ds.posnr, ds.segnr, 
    listagg((select distinct max(li1.paco) from leos_item li1 where li.av_part_no = li1.av_part_no and li.paco is not null), ', ') within group (order by pd.part_no) inq_no
    from oes_delsegview ds, oes_address ad, oes_opos op, oes_nrbom nr, scm_prodtyp sp, leos_item li, part_description pd
    where ds.delnr = ad.key
    and ad.adr = ds.deladr
    and ds.pos_o_status not in ('9', 'D')
    and ds.pos_c_status not in ('9', 'D')
    and ds.seg_o_status not in ('9', 'D')
    and ds.seg_c_status not in ('9', 'D')
    and ds.cunr in ('W31170','W31172')
    and ds.pos_type != 'RC'
    and ds.ordnr = op.ordnr
    and ds.posnr = op.posnr
    and ds.catnr = pd.catnr
    and ds.prodtyp = pd.prodtyp
    and ds.packtyp = pd.packtyp
    and ds.catnr = nr.p_catnr (+)
    and ds.prodtyp = nr.p_prodtyp (+)
    and ds.packtyp = nr.p_packtyp (+)
    and nr.c_prodtyp = sp.prodtyp (+) 
    and sp.prodgrp (+) = 'COMP'
    and substr(nr.c_prodtyp,1,2) not in ('MT','LF')
    and nr.c_catnr = li.catnr (+)
    and nr.c_prodtyp = li.prodtyp (+)
    and nr.c_packtyp = li.packtyp (+)
    and pd.catnr = '9780007938797'
    group by ds.catnr,ds.planqty, ds.ordnr, ds.posnr, ds.segnr

回答2:

I used a regexp_replace function to remove duplicates in my listagg;

regexp_replace(
    listagg((select distinct max(li1.paco) from leos_item li1 where li.av_part_no = li1.av_part_no and li.paco is not null), ', ') within group (order by pd.part_no) 
    ,'([^,]+)(,\1)+', '\1') inq_no

Appears to work OK.

LISTAGG in oracle to return distinct values

回答3:

You can do it via RegEx replacement. Here is an example:

-- Citations Per Year - Cited Publications main query. Includes list of unique associated core project numbers, ordered by core project number.
SELECT ptc.pmid AS pmid, ptc.pmc_id, ptc.pub_title AS pubtitle, ptc.author_list AS authorlist,
  ptc.pub_date AS pubdate,
  REGEXP_REPLACE( LISTAGG ( ppcc.admin_phs_org_code || 
    TO_CHAR(ppcc.serial_num,'FM000000'), ',') WITHIN GROUP (ORDER BY ppcc.admin_phs_org_code || 
    TO_CHAR(ppcc.serial_num,'FM000000')),
    '(^|,)(.+)(,\2)+', '\1\2')
  AS projectNum
FROM publication_total_citations ptc
  JOIN proj_paper_citation_counts ppcc
    ON ptc.pmid = ppcc.pmid
   AND ppcc.citation_year = 2013
  JOIN user_appls ua
    ON ppcc.admin_phs_org_code = ua.admin_phs_org_code
   AND ppcc.serial_num = ua.serial_num
   AND ua.login_id = 'EVANSF'
GROUP BY ptc.pmid, ptc.pmc_id, ptc.pub_title, ptc.author_list, ptc.pub_date
ORDER BY pmid;

回答4:

Super simple answer solved

select
regexp_replace('14/061127-12, 14/061127-16, 14/061127-16','([^,]+)(,\1)*(,|$)', '\1\3')


from dual

14/061127-12, 14/061127-16

see my full answer here

来源：https://stackoverflow.com/questions/35298782/oracle-unique-listagg-values

标签

sql

Oracle

oracle10g

listagg