问题
I had asked a question about How to open option list of HTML select tag on onfocus(). At that time it solved my problem but I missed one problem that every time on opening a html select option onfocus
next select option went disappear.
I not able to find whats going wrong with this code. here is link for that problematic question jsFiddle.
回答1:
Yes, that's what the lines
var x = "select[tabindex='" + (parseInt($(this).attr('tabindex'),10) + 1) + "']";
$(x).fadeTo(50,0);
do. They hide the next select, because otherwise it would show on top of the expanded one.
This isn't a good solution at all though. Instead i'd use z-index to prevent that from happening:
$('select').focus(function(){
$(this).attr("size",$(this).attr("expandto")).css('z-index',2);
});
$('select').blur(function(){
$(this).attr("size",1).css('z-index','1');
});
$('select').change(function(){
$(this).attr("size",1).css('z-index','1');
});
It would be even better to use a class instead of inline style. But i used that just as a demonstration.
http://jsfiddle.net/PpTeF/1/
回答2:
Just comment out the fadeTo function. check this http://jsfiddle.net/PpTeF/2/
$(document).ready(function(){
$('select').focus(function(){
$(this).attr("size",$(this).attr("expandto"));
var x = "select[tabindex='" + (parseInt($(this).attr('tabindex'),10) + 1) + "']";
//$(x).fadeTo(50,0);
});
$('select').blur(function(){
$(this).attr("size",1);
var x = "select[tabindex='" + (parseInt($(this).attr('tabindex'),10) + 1) + "']";
//$(x).fadeTo('fast',1.0);
});
$('select').change(function(){
$(this).attr("size",1);
var x = "select[tabindex='" + (parseInt($(this).attr('tabindex'),10) + 1) + "']";
//$(x).fadeTo('fast',1.0);
});
});
Cheers!!
来源:https://stackoverflow.com/questions/18226939/opening-a-html-select-option-on-focus