问题
i have this data and i am trying to find cases where there are different ids but duplicate data in Field 1,2,3,4
id field1 field2 field3 field4
==== ====== ====== ===== =======
1 A B C D
2 A B C D
3 A A C B
4 A A C B
so, in whatever way possible, in this case i want it to somehow show me:
1 & 2 are duplicates 3 & 4 are duplicates
回答1:
Instead of SELECT DISTINCT
, select the fields and a count of rows. Use HAVING
to filter out items with more than one row, e.g:
select field1
,field2
,field3
,field4
,count (*)
from foo
group by field1
,field2
,field3
,field4
having count (*) > 1
You can then join your original table back against the results of the query.
回答2:
One way to do this is to use having and group by
esben=# select * from test;
id | a | b | c | d
----+---+---+---+---
1 | 1 | 2 | 3 | 4
2 | 1 | 2 | 3 | 4
3 | 1 | 1 | 3 | 2
4 | 1 | 1 | 3 | 2
(4 rows)
esben=# select count(id),a,b,c,d from test group by a,b,c,d having count(id) >1;
count | a | b | c | d
-------+---+---+---+---
2 | 1 | 2 | 3 | 4
2 | 1 | 1 | 3 | 2
(2 rows)
This doesn't list the actual id's though, but without the actual output you want it is hard to tell you how to get about that.
回答3:
SELECT *
FROM [TableName]
WHERE ID IN(SELECT MIN(ID)
FROM [TableName]
GROUP BY CONCAT(field1, field2, field3, field4))
This will return the full row for id's 1 & 3
来源:https://stackoverflow.com/questions/1503080/sql-query-distinct-on-multiple-columns