Django 'ascii' codec can't encode character

问题

In Django I want to use a simple template tag to truncate data.

This is what I have so far:

@register.filter(name='truncate_simple')
def truncate_char_to_space(value, arg):
    """
    Truncates a string after a given length.
    """
    data = str(value)
    if len(value) < arg:
        return data

    if data.find(' ', arg, arg+5) == -1:
        return data[:arg] + '...'
    else:
        return data[:arg] + data[arg:data.find(' ', arg)] + '...'

But when I use it I get the following error:

{{ item.content|truncate_simple:5  }}

Error:

'ascii' codec can't encode character u'\u2013' in position 84: ordinal not in range(128)

Error is on line starting data = str(value)

Why?

回答1:

try to use unicode() to convert value (instead of str()):

data = unicode(value)

回答2:

If you're using django and python 2.7 this fixes it for me:

from django.utils.encoding import python_2_unicode_compatible

@python_2_unicode_compatible
class Utente(models.Model):

see https://docs.djangoproject.com/en/dev/ref/utils/#django.utils.encoding.python_2_unicode_compatible

回答3:

@max4ever 's answer works for me. also sometimes you should put this line in the head of python files:

from __future__ import unicode_literals

it can be helpful when solving unicode encoding issues like this one.

回答4:

in settings.py add this

import sys
reload(sys)
sys.setdefaultencoding('UTF8')

来源：https://stackoverflow.com/questions/17974412/django-ascii-codec-cant-encode-character