is it possible to convert bitset<8> to an array of characters of integers?

问题

I have bitset<8> v8 and its value is something like "11001101", something in binary, how can we convert it to an array of characters or integers in c++?

回答1:

To convert to an array of char, you could use the bitset::to_string() function to obtain the string representation and then copy individual characters from that string:

#include <iostream>
#include <algorithm>
#include <string>
#include <bitset>
int main()
{
        std::bitset<8> v8 = 0xcd;

        std::string v8_str = v8.to_string();
        std::cout << "string form: " << v8_str << '\n';

        char a[9] = {0}; 
        std::copy(v8_str.begin(), v8_str.end(), a);
        // or even strcpy(a, v8_str.c_str());
        std::cout << "array form: " << a << '\n';
}

回答2:

vector<int> ints;
for(int i = 0 ; i < v8.size() ; i++ )
{
     ints.push_back(v8[i]);
}

Likewise, you can make an array of chars. Or you may use raw array as:

char chars[8];
for(int i = 0 ; i < v8.size() ; i++ )
{
     chars[i] = v8[i];
}

来源：https://stackoverflow.com/questions/5005863/is-it-possible-to-convert-bitset8-to-an-array-of-characters-of-integers