How to get current tab index in Flutter

问题

In flutter implementing a tab layout is easy and straightforward. This is a simple example from the official documentation:

import 'package:flutter/material.dart';

void main() {
  runApp(new TabBarDemo());
}

class TabBarDemo extends StatelessWidget {
  @override
  Widget build(BuildContext context) {
    return new MaterialApp(
      home: new DefaultTabController(
        length: 3,
        child: new Scaffold(
          appBar: new AppBar(
            bottom: new TabBar(
              tabs: [
                new Tab(icon: new Icon(Icons.directions_car)),
                new Tab(icon: new Icon(Icons.directions_transit)),
                new Tab(icon: new Icon(Icons.directions_bike)),
              ],
            ),
            title: new Text('Tabs Demo'),
          ),
          body: new TabBarView(
            children: [
              new Icon(Icons.directions_car),
              new Icon(Icons.directions_transit),
              new Icon(Icons.directions_bike),
            ],
          ),
        ),
      ),
    );
  }
}

But here is the thing, I want to get the active tab index so I can apply some logic on certain tabs. I search the documentation but I wasn't able to figure it out. Can you guys help and thanks?

回答1:

The whole point of DefaultTabController is for it to manage tabs by itself.

If you want some custom tab management, use TabController instead. With TabController you have access to much more informations, including the current index.

class MyTabbedPage extends StatefulWidget {
  const MyTabbedPage({Key key}) : super(key: key);
  @override
  _MyTabbedPageState createState() => new _MyTabbedPageState();
}

class _MyTabbedPageState extends State<MyTabbedPage>
    with SingleTickerProviderStateMixin {
  final List<Tab> myTabs = <Tab>[
    new Tab(text: 'LEFT'),
    new Tab(text: 'RIGHT'),
  ];

  TabController _tabController;

  @override
  void initState() {
    super.initState();
    _tabController = new TabController(vsync: this, length: myTabs.length);
  }

  @override
  void dispose() {
    _tabController.dispose();
    super.dispose();
  }

  @override
  Widget build(BuildContext context) {
    return new Scaffold(
      appBar: new AppBar(
        bottom: new TabBar(
          controller: _tabController,
          tabs: myTabs,
        ),
      ),
      body: new TabBarView(
        controller: _tabController,
        children: myTabs.map((Tab tab) {
          return new Center(child: new Text(tab.text));
        }).toList(),
      ),
    );
  }
}

回答2:

In this case, using StatefulWidget and State isn't a good idea.

You can get current index by DefaultTabController.of(context).index;.

Follow the code:

...
appBar: AppBar(
  bottom: TabBar(
    tabs: [
      Tab(~), Tab(~)
    ]
  ),
  actions: [
    // At here you have to get `context` from Builder.
    // If you are not sure about this, check InheritedWidget document.
    Builder(builder: (context){
      final index = DefaultTabController.of(context).index;   
      // use index at here... 
    })
  ]
)

回答3:

You can access the current index when the tab is selected by onTap event of TabBar.

TabBar(
    onTap: (index) {
      //your currently selected index
    },

    tabs: [
      Tab1(),
      Tab2(),
    ]);

回答4:

Just apply a listener on the TabController.

// within your initState() method
_tabController.addListener(_setActiveTabIndex);

void _setActiveTabIndex() {
  _activeTabIndex = _tabController.index;
}

回答5:

Thanks to the example of Rémi Rousselet, you can do it, the code like this:

_tabController.index

This will return the current index of the position of your TabBarView

来源：https://stackoverflow.com/questions/50123354/how-to-get-current-tab-index-in-flutter

标签

Flutter

tabcontrol

flutter-layout