问题
I need to call the require on a lua file that will not always be in the same place. I was trying to call require on the full path name but that doesn't seem to be working either. I even tried replacing one of my working normal requires with a correct full path name to the same file
example changing require "foo" to require "C:\Users\Me\MyLuaProject\foo"
but when i switched it to the full path name it could no longer find it. So I am wondering if you can even call require on a full path and if not how would i achieve the same result differently?
回答1:
Add the directory containing the file to package.path:
package.path = package.path .. ";C:\\Users\\Me\\MyLuaProject"
require "foo"
You can also add it to the LUA_PATH environment variable, but this is probably less easy to modify on the fly.
A common pattern for modules is to have abc.lua and abc/xyz.lua; to require files in a subdirectory like that, use the following:
require "abc"
require "abc.xyz"
回答2:
If you just need to load a file, use dofile, which takes a path:
dofile("C:\\Users\\Me\\MyLuaProject\\foo")
来源：https://stackoverflow.com/questions/11868847/lua-require-function-on-a-full-path-name