Can I use the range operator with if statement in Swift?

问题

Is it possible to use the range operator ... and ..< with if statement. Maye something like this:

let statusCode = 204
if statusCode in 200 ..< 299 {
  NSLog("Success")
}

回答1:

You can use the "pattern-match" operator ~=:

if 200 ... 299 ~= statusCode {
    print("success")
}

Or a switch-statement with an expression pattern (which uses the pattern-match operator internally):

switch statusCode {
case 200 ... 299:
    print("success")
default:
    print("failure")
}

Note that ..< denotes a range that omits the upper value, so you probably want 200 ... 299 or 200 ..< 300.

Additional information: When the above code is compiled in Xcode 6.3 with optimizations switch on, then for the test

if 200 ... 299 ~= statusCode

actually no function call is generated at all, only three assembly instruction:

addq    $-200, %rdi
cmpq    $99, %rdi
ja  LBB0_1

this is exactly the same assembly code that is generated for

if statusCode >= 200 && statusCode <= 299

You can verify that with

xcrun -sdk macosx swiftc -O -emit-assembly main.swift

As of Swift 2, this can be written as

if case 200 ... 299 = statusCode {
    print("success")
}

using the newly introduced pattern-matching for if-statements. See also Swift 2 - Pattern matching in "if".

回答2:

This version seems to be more readable than pattern matching:

if (200 ... 299).contains(statusCode) {
    print("Success")
}

回答3:

This is an old thread, but it seems to me we're over-thinking this. It seems to me the best answer is just

if statusCode >= 200 && statusCode <= 299

There's no

if 200 > statusCode > 299

form that I'm aware of, and the other suggested solutions are doing function calls, which will be slower and are harder to read. The pattern match method is a useful trick to know, but seems like a poor fit for this problem

回答4:

I wanted to check 4xx errors except 401. Here is the code:

let i = 401

if 400..<500 ~= i, i != 401 {
    print("yes")
} else {
    print("NO")
}

回答5:

I preffered Range .contains() operator too, until found that its implementation is inefficient - https://oleb.net/blog/2015/09/swift-ranges-and-intervals/

We can represent the condition x < 0 using a range: (Int.min..<0).contains(x) is exactly equivalent. It is vastly slower, though. The default implementation of contains(_:) traverses the entire collection, and executing a loop nine quintillion times in the worst case is not cheap.

来源：https://stackoverflow.com/questions/24893110/can-i-use-the-range-operator-with-if-statement-in-swift

标签

if-statement

swift

range