问题
We are using SQL Server.
In our CASE WHEN statement, I need to check if the number of days between the 2 dates are > 3 business days (so excluding weekends and holidays).
CASE WHEN end_date - start_date > 3 THEN 0 --> this need to exclude
weekend and holidays
WHEN CODE = 1 THEN 1
WHEN CODE =2 THEN 2
ELSE 3
END AS MyColumn
Say I have a holiday calendar table that has column HolidayDates that contains all the holidays, for ex: 12/25/2018, 12/31/2018, etc.
HolidayDates 12/25/2018 12/31/2018 So, if
Date1 = 1/2/19 (Wednesday)
Date2 = 12/27/18 (Thursday)
The number of business days in between Date1 and Date2 is 3 days (12/27, 12/28 and 12/31).
The above query will get the number of business days including weekends and holidays.
How do I also exclude weekends and holidays in the query ?
Thank you.
Edited with answer:
select start_date, end_date,
datediff(day, mt.start_date, mt.end_date) datediff,
(select
(datediff(wk, mt.start_date, mt.end_date) )
+(case when datename(dw, mt.start_date) = 'sunday' then 1 else 0 end)
+(case when datename(dw, mt.end_date) = 'saturday' then 1 else 0 end)
) weekend,
(select count(*) from HolidayDates hd
where hd.holydayDate between mt.start_date and mt.end_date
) as [holydays (not weekends)],
datediff(day, mt.start_date, mt.end_date)
-(select
(datediff(wk, mt.start_date, mt.end_date) )
+(case when datename(dw, mt.start_date) = 'sunday' then 1 else 0 end)
+(case when datename(dw, mt.end_date) = 'saturday' then 1 else 0 end)
) * 2
-(select count(*) from HolidayDates hd
where hd.holydayDate between mt.start_date and mt.end_date
)
as diff
from MyTable mt
回答1:
create table MyTable
(
start_date date not null,
end_date date not null,
code int not null
)
GO
create table HolidayDates
(
holydayDate date not null,
holydayDescription varchar(100) not null
)
GO
insert into MyTable
values
('2018-12-25','2019-01-01',101)
,('2018-12-01','2019-01-31',102)
,('2018-12-24','2019-01-02',103)
GO
insert into HolidayDates
values
('2018-12-25', 'xmas')
,('2019-01-01', 'Reveillon')
GO
In the below query you can see the how the columns are calculated.
[holydays (not weekends)]: get all holydays form your table are not also weekends (so they are not counted twice).
weekends: get weekends in the period.
The rest os the columns can be self-explanatory
Disclaimer, you can simplify this a bit, it's just an example query in how to use
DATEPART
DATEDIFF
DATNAME
select
datediff(day, mt.start_date, mt.end_date) as [total days],
(
select
count(*)
from
HolidayDates hd
where
hd.holydayDate between mt.start_date
and mt.end_date
and DATEPART(WEEKDAY, hd.holydayDate) between 2
and 6
) as [holydays (not weekends) ],
(
select
(
datediff(wk, mt.start_date, mt.end_date) * 2
) +(
case when datename(dw, mt.start_date) = 'sunday' then 1 else 0 end
) +(
case when datename(dw, mt.end_date) = 'saturday' then 1 else 0 end
)
) as weekends,
case when datediff(day, mt.start_date, mt.end_date) -(
select
(
datediff(wk, mt.start_date, mt.end_date) * 2
) +(
case when datename(dw, mt.start_date) = 'sunday' then 1 else 0 end
) +(
case when datename(dw, mt.end_date) = 'saturday' then 1 else 0 end
)
) -(
select
count(*)
from
HolidayDates hd
where
hd.holydayDate between mt.start_date
and mt.end_date
and DATEPART(WEEKDAY, hd.holydayDate) between 2
and 6
) > 3 then 0 --> this need to exclude weekend and holidays
when mt.code = 1 then 1 when mt.code = 2 then 2 else 3 end as mycolumn
from
MyTable mt
RETURNS
total days holydays (not weekends) weekends mycolumn
----------- ----------------------- ----------- -----------
7 2 2 3
61 2 18 0
9 2 2 0
(3 row(s) affected)
来源：https://stackoverflow.com/questions/54467132/sql-server-query-to-get-the-number-of-business-days-between-2-dates-excluding-h