问题
I am trying to build a tool which will run an index match in a cell on a spreadsheet, and then display the result of the formula in python. My understanding is Openpyxl will not actually run the formulas but I can write to excel and then refresh the file to run it?
from openpyxl import load_workbook
path= "C:\\Users\\Me\\Documents\\Python\\File.xlsx"
myworkbook=load_workbook(path)
worksheet=myworkbook.get_sheet_by_name('Sheet1')
mycell=worksheet['B2']
mycell.value="index(B4:B72,match(B1,A4:A72,0))"
print(mycell)
Anyway, I receive and error and I am not sure what is going on. Ouput:
DeprecationWarning: Call to deprecated function get_sheet_by_name (Use wb[sheetname]). worksheet=myworkbook.get_sheet_by_name('Sheet1')
Process finished with exit code 0
To be clear, the formula works if I just do it in Excel because B1 is populated in the file.
I am not sure what the output is doing. It is not throwing an error but I have no idea what <Cell 'Sheet1'.B2> and "Process Finished with Exit code 0" is trying to tell me. I expected a string output because the I am trying to index in a sentence.
回答1:
A) Running the formulas requires opening the file in Excel. As you state:
My understanding is Openpyxl will not actually run the formulas but I can write to excel and then refresh the file to run it?
If by "refresh the file to run it" you mean open the file in Excel, then yes, Excel will execute the formula.
B) The error you get is actually just a warning telling you that a feature you used will not be available in future versions of Openpyxl. In this case, the warning also tells you the correct way to acccess the sheet.
Call to deprecated function get_sheet_by_name (Use wb[sheetname]) [emphasis added]
To avoid the warning, replace the line with:
worksheet=myworkbook['Sheet1']
C) When you add a formula to a cell using Openpyxl, you have to include the = character at the beginning of the formula, so your line should be:
mycell.value="=index(B4:B72,match(B1,A4:A72,0))"
D) In your print statement, you pass it the mycell object, which is why it prints the 'name' of the object <Cell 'Sheet1'.B2>. This could be useful if you want to verify that your mycell variable is pointing to the correct cell in the workbook, but it isn't what you want. To access the contents of a cell, you need to refer to the .value of that cell. Modify your print statement to be:
print(mycell.value)
Putting all of that together:
from openpyxl import load_workbook
path= "C:\\Users\\Me\\Documents\\Python\\File.xlsx"
myworkbook=load_workbook(path)
worksheet=myworkbook['Sheet1']
mycell=worksheet['B2']
mycell.value="=index(B4:B72,match(B1,A4:A72,0))"
print(mycell.value)
来源：https://stackoverflow.com/questions/58250488/using-pythons-openpyxl-for-an-index-match