问题
I want to create a function that performs a certain task only when a hex value indicates an upper or lower case letter, i.e., when the hex code is between 20 and 7A. Is there a way to make a statement in python that is logically equivalent to:
if a >= 20 and a <= 7A: perform stuff
? Do I just throw a 0x in front of it and magic happens?
回答1:
yes ... you just throw a 0x and it becomes numeric ....
or int("7A",16) == 0x7A
0x20 <= a <= 0x7A you can also chain comparison operators like this (which translates roughly to "is a between val1 and val2")
来源：https://stackoverflow.com/questions/13366323/using-comparison-operators-for-hex-values