Swift - Sort array of versions as strings

问题

I have an array of strings (of an app's versions) randomly ordered like:

var arrayOfStrings = ["2.12.5", "2.12.10", "2.2", "2.11.8"]

The sorted array should be ["2.2", "2.12.10", "2.12.5", "2.11.8"] (ordered by most recent). I am trying to sort it.

EDIT: My bad, the sorted array should actually be ["2.12.10", "2.12.5", "2.11.8", "2.2"]. Use the solution above.

//Compare by string
array.sortInPlace({ //This returns ["2.2", "2.12.5", "2.12.10", "2.11.8"]
    $0 > $1
})

//Compare by int
array.sortInPlace({ //This returns ["2.12.10", "2.12.5", "2.11.8", "2.2"]
    Int($0.stringByReplacingOccurrencesOfString(".", withString: "")) > Int($1.stringByReplacingOccurrencesOfString(".", withString: ""))
})

None of this is working properly. What is the best way to return the correct array?

回答1:

The easiest option is to use compare with .NumericSearch:

arrayOfStrings.sortInPlace { $0.compare($1, options: .NumericSearch) == .OrderedAscending }

Obviously, if you want it in descending order, use .OrderedDescending.

回答2:

You have to split the version string into its components, convert them to numbers and compare their numeric values. Try this:

var arrayOfStrings = ["2.12.5", "2.12.10", "2.2", "2.11.8"]

arrayOfStrings.sortInPlace {
    let v0 = ($0 as NSString).componentsSeparatedByString(".")
    let v1 = ($1 as NSString).componentsSeparatedByString(".")

    for i in 0..<min(v0.count, v1.count) {
        if v0[i] != v1[i] {
            return Int(v0[i]) < Int(v1[i])
        }
    }

    return v0.count < v1.count
}

This obviously cannot handle version numbers like 2.1a or 3.14b123

回答3:

Swift 4 version:

var arrayOfStrings = ["2.12.5", "2.12.10", "2.2", "2.11.8"]

arrayOfStrings.sorted { (lhs, rhs) in
    let lhsc = lhs.components(separatedBy: ".")
    let rhsc = rhs.components(separatedBy: ".")
    for i in 0..<min(lhsc.count, rhsc.count) where lhsc[i] != rhsc[i] {
        return (Int(lhsc[i]) ?? 0) < (Int(rhsc[i]) ?? 0)
    }
    return lhsc.count < rhsc.count
}

回答4:

Swift 4.2:

var arrayOfStrings = ["1.2.1", "1.0.6", "1.1.10"]
arrayOfStrings.sort { (a, b) -> Bool in
    a.compare(b, options: String.CompareOptions.numeric, range: nil, locale: nil) == .orderedAscending
}
print(arrayOfStrings) // ["1.0.6", "1.1.10", "1.2.1"]

来源：https://stackoverflow.com/questions/35815469/swift-sort-array-of-versions-as-strings

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arrays

string

swift

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