How to return all the free periods of time from an appointment set

问题

Using the following screenshot to show an example of the data set,

int,datetime2,datetime2, int

How can i return all the free periods of time which are available within the start and stop ranges which are also equal or longer than the slot duration parameter when they are not stored in the database as appointments

declare @startRange datetime2
declare @endRange datetime2
declare @slotDurationInMinutes int

set @startRange = '2016-06-06T22:00:00.000Z'
set @endRange = '2016-06-07T21:59:00.000Z'
set @slotDurationInMinutes = 30


-- from this appointment dataset how do i query for all the free periods which are as long or longer than the slotduration parameter
-- these values are not stored in the table?
select TSO_Table_ID, time_start, time_end, duration from Org_TSO_Table

For example the expected output of a query where the slotduration param is 30 minutes would be:

free_from=2016-06-06T22:00:00.000Z free_until=2016-06-06T22:00:30.000Z

(This record contains the search range start value)

free_from=2016-06-06T22:01:30.000Z free_until=2016-06-06T22:04:00.000Z

free_from=2016-06-06T22:04:20.000Z free_until=2016-06-06T22:10:00.000Z

free_from=2016-06-06T22:11:00.000Z free_until=2016-06-06T22:11:30.000Z

free_from=2016-06-06T22:12:30.000Z free_until=2016-06-07T21:59:00.000Z

(This record contains the search range end value)

回答1:

It's hard to say if the solution below will work for you, given the small data sample, but hopefully it will get you started.

IF OBJECT_ID('tempdb..#sked') is not null
DROP TABLE #sked

IF OBJECT_ID('tempdb..#tmpResults') is not null
DROP TABLE #tmpResults

create table #sked(
    ID int,
    time_start datetime2,
    time_end datetime2,
    duration int)

insert into #sked (ID,time_start,time_end,duration) values
(4,'2016-06-06 00:30:00','2016-06-06 01:30:00',3600000),
(2,'2016-06-06 04:00:00','2016-06-06 04:20:00',1200000),
(1,'2016-06-06 10:00:00','2016-06-06 11:00:00',3600000),
(6,'2016-06-06 11:30:00','2016-06-06 12:30:00',3600000)

declare @startRange datetime2
declare @endRange datetime2
declare @slotDurationInMinutes int

set @startRange = '2016-06-05T00:00:00.000'
set @endRange = '2016-06-07T21:59:00.000'
set @slotDurationInMinutes = 30

select
    time_end as free_from,
    isnull(lead(time_start) over (order by time_end),@endRange) as free_until
into #tmpResults
from
    #sked
where
    time_end >= @startRange 
    and time_end <= @endRange
    --and duration <= (@slotDurationInMinutes * 60000) --conversion to milliseconds

union all

select
    case when @startRange < min(time_start) then @startRange end as free_from,
    case when @startRange < min(time_start) then min(time_start) end as free_until
from
    #sked
where
    time_end >= @startRange 
    and time_end <= @endRange
    --and duration <= (@slotDurationInMinutes * 60000) --conversion to milliseconds
order by
    free_from

select 
    *,
    DATEDIFF(minute,free_from,free_until) 
from 
    #tmpResults
where
    free_from is not null
    and DATEDIFF(minute,free_from,free_until) >= @slotDurationInMinutes

来源：https://stackoverflow.com/questions/37674964/how-to-return-all-the-free-periods-of-time-from-an-appointment-set