fill in NA based on the last non-NA value for each group in R [duplicate]

问题

This question already has answers here:

Replace missing values (NA) with most recent non-NA by group (6 answers)

Closed 4 years ago.

My question is I have a dataframe m as below

y1 =c( rep("A",5),rep("B",5))
y2 = rep(c(1:5),2)
y3 = y2
y3[c(2,7,9)]=NA
m = data.frame(y1,y2,y3)

   y1 y2   y3
1   A  1    1
2   A  2 <NA>
3   A  3    3
4   A  4    4
5   A  5    5
6   B  1    1
7   B  2 <NA>
8   B  3    3
9   B  4 <NA>
10  B  5    5

I want to fill in the NA based on the closest non-NA value "in front of" this NA. My output should look like this:

   y1 y2   y3 y4
1   A  1    1  1
2   A  2 <NA>  1
3   A  3    3  3
4   A  4    4  4
5   A  5    5  5
6   B  1    1  1
7   B  2 <NA>  1
8   B  3    3  3
9   B  4 <NA>  3
10  B  5    5  5

Any idea about how to use dplyr to achieve this goal?

回答1:

This may have been answered before, but I don't know if it's been answered in a dplyr context. zoo::na.locf() is your friend:

m %>% group_by(y1) %>% mutate(y4=zoo::na.locf(y3))

来源：https://stackoverflow.com/questions/27207162/fill-in-na-based-on-the-last-non-na-value-for-each-group-in-r