How to replace a pattern with newline (\n) with sed under UNIX / Linux operating systems?

问题

I have a txt file which contains:

Some random
text here. This file
has multiple lines. Should be one line.

I use:

sed '{:q;N;s/\n/:sl:/g;t q}' file1.txt > singleline.txt

and get:

Some random:sl:text here. This file:sl:has multiple lines. Should be one line.

Now I want to replace the :sl: pattern with newline (\n) character. When I use:

sed 's/:sl:/&\n/g' singleline.txt

I get:

Some random:sl:
text here. This file:sl:
has multiple lines. Should be one line.

How to replace the pattern with newline character instead of adding newline character after the pattern?

回答1:

Sed uses & as a shortcut for the matched pattern. So you are replacing :s1: with :s1:\n.

Change your sed command like this:

sed 's/:sl:/\n/g' singleline.txt

回答2:

You can do it more easily with tr : tr '\n' ' ' < singleline.txt

来源：https://stackoverflow.com/questions/23940591/how-to-replace-a-pattern-with-newline-n-with-sed-under-unix-linux-operating