) I'm in a process of creating a memory game. My problem is that whenever i click for the second time, i can't even see toggled button. To be clear - first click toggles the togglebutton, so i can see the number it holds, the second click on a different togglebutton is suposed to toggle it, show me the number and then proceed to either set a score +1 if numbers are the same, or reverse them back again if they're different.
Below is the code that i use as my onClick function, i've been thinking about putting some kind of sleep or delay function somwhere in the second "if block" - (if(klikniecia ==2)).
Any help on this topic would be appreciated.
public void onClick(View view) {
for (int i = 0; i < karta.length; i++){
if (view == karta[i]){
karta[i].setEnabled(false);
klikniecia++;
if (klikniecia == 1){
kartaID[0]=i;
kartaWartosc[0]=listaKart.get(i);
}
if (klikniecia == 2){
kartaID[1]=i;
kartaWartosc[1]=listaKart.get(i);
//i think, about setting a delay here, so i can see both of the cards, regardles if the're the same or not before reverting them.
if (czyPara()){
karta[kartaID[0]].setEnabled(false);
karta[kartaID[1]].setEnabled(false);
klikniecia=0;
}
else{
karta[kartaID[0]].setEnabled(true);
karta[kartaID[0]].toggle();
karta[kartaID[1]].setEnabled(true);
karta[kartaID[1]].toggle();
klikniecia=0;
}
}
}
}
}
Instead of sleeping in the onclick, you could post a delayed message to a handler (with associated runnable) and have it update the UI. Obviously fit this into the design of your app and make it work, but the basic idea is this:
//Here's a runnable/handler combo
private Runnable mMyRunnable = new Runnable()
{
@Override
public void run()
{
//Change state here
}
};
Then from onClick you post a delayed message to a handler, specifying that runnable to be executed.
Handler myHandler = new Handler();
myHandler.postDelayed(mMyRunnable, 1000);//Message will be delivered in 1 second.
Depending on how complicated your game is, this might not be exactly what you want, but it should give you a start.
Correctly work:
final Handler handler = new Handler();
handler.postDelayed(new Runnable() {
@Override
public void run() {
//Do something after 100ms
}
}, 100);
You never should sleep in UI thread (by default all your code runs in UI thread) - it will only make UI freeze, not let something change or finish. I can't suggest more because I don't understand code logic.
Do not sleep in the UI thread. You need another thread that will look for a "wake up and wait" message from your UI thread. That second thread could then do your hiding after a normal sleep call. You could then keep the thread around for the next time you need to hide something, or kill it and whip up a new one each time you need another delay.
I believe there are some "postFoo" functions that might be useful in this context (triggering UI events from outside the UI thread).
b.setOnClickListener(new OnClickListener() {
public void onClick(View arg0) {
// TODO Auto-generated method stub
final ProgressDialog myPd_ring=ProgressDialog.show(MainActivity.this, "confident checker", "calculating please wait..", true);
myPd_ring.setCancelable(true);
new Thread(new Runnable() {
public void run() {
// TODO Auto-generated method stub
try
{
Thread.sleep(5000);
}
catch(Exception e){}
b.dismiss();
}
}).start();
final Handler handler = new Handler();
handler.postDelayed(new Runnable() {
public void run() {
Toast.makeText(getApplicationContext(), "today your confident level is 90% ",
Toast.LENGTH_LONG).show();
}
}, 5000);
}
});
来源：https://stackoverflow.com/questions/4199191/how-to-set-delay-in-android-onclick-function