Combining two #defined symbols in C++ preprocessor

问题

I want to do:

#define VERSION XY123
#define PRODUCT MyApplication_VERSION

so that PRODUCT is actually MyApplication_XY123. I have tried playing with the merge operator ## but with limited success...

#define VERSION XY123
#define PRODUCT MyApplication_##VERSION

=> MyApplication_VERSION

#define VERSION XY123
#define PRODUCT MyApplication_##(VERSION)

=> MyApplication_(XY123) - close but not quite

Is what I want possible?

回答1:

Token pasting works with arguments to macros. So try this

#define VERSION XY123
#define PASTE(x) MyApplication_ ## x
#define PRODUCT PASTE(VERSION)

回答2:

The ## operator acts before argument substitution has taken place. The classical solution is to use a helper:

#define CONCAT2(a, b) a ## b
#define CONCAT(a, b) CONCAT2(a, b)

CONCAT(MyApplication_, VERSION)

回答3:

All problems in computer science can be solved by an extra level of indirection:

#define JOIN_(X,Y) X##Y
#define JOIN(X,Y) JOIN_(X,Y)
#define VERSION XY123
#define PRODUCT JOIN(MyApplication_,VERSION)

来源：https://stackoverflow.com/questions/16591642/combining-two-defined-symbols-in-c-preprocessor