问题
I'm trying to understand how exactly memory indirect addressing works in assembly language with AT&T syntax.
movl (%eax), %ebx
movl %eax, (%ebx)
Here is a similar question that explains about memory indirect addressing
This is what I've understood:
In the first case, you load the data pointed to by the register %eax and store it in %ebx.
In the second case, you store the data in the register %eax to the address space pointed to by the register %ebx. Am I correct?
回答1:
Basically the syntax is
movl source, destination
So movl (%eax), %ebx is indeed copy the value at address pointed to by %eax into %ebx. And movl %eax, (%ebx) is copy the value inside register %eax into the address pointed to by %ebx.
So indeed your understanding is correct.
来源：https://stackoverflow.com/questions/17020739/memory-indirect-addressing-movl-assembly