Access “this” inside of static codeblocks

僤鯓⒐⒋嵵緔 提交于 2019-12-06 11:24:22

Is there any way I can write this without specifically need to call typeof() for the class i'm specifically inside of?

No, this is likely the best option. If you know you are never going to add any other fields, of any other types, you can just skip the Where clause.

In addition, you should use ToList() to prevent the IEnumerable<T> generated from having to rerun each time it's enumerated:

private static readonly Lazy<IEnumerable<MyTypeCode>> AllMyTypeCodes =
    new Lazy<IEnumerable<MyTypeCode>>(() =>
    {
        return typeof(MyTypeCodes)
             .GetFields(BindingFlags.Static | BindingFlags.Public)
             // If you're not using any other fields, just skip this
             // .Where(x => x.FieldType == typeof (MyTypeCode ))
             .Select(x => (MyTypeCode) x.GetValue(null))
             .ToList();                 
    });

Make a private constructor that gives you a (privately held) reference.

private MyTypeCodes() { }
private static MyTypeCodes _instance = new MyTypeCodes();

public static DoSomethingWithType()
{
  return _instance.GetType().foo();
}

Or you could have the constructor call GetType() and just use that instead of calling _instance.GetType() every time you need it.

If you prefer the semantics, you could do:

private static readonly Type _thisType = typeof(MyTypeCodes);

// use like
var typeCodes = _thisType.GetFields(...
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