How to find a subarray with minimum k length and maximum sum?

只愿长相守 提交于 2019-12-05 20:53:22
Evgeny Panasyuk

Solution based on this answer

Live demo

#include <algorithm>
#include <iterator>
#include <iostream>
#include <numeric>
#include <ostream>
#include <utility>
#include <vector>

// __________________________________________________

template<typename RandomAccessIterator> typename std::iterator_traits<RandomAccessIterator>::value_type
max_subarr_k(RandomAccessIterator first,RandomAccessIterator last,int k)
{
    using namespace std;
    typedef typename iterator_traits<RandomAccessIterator>::value_type value_type;
    if(distance(first,last) < k)
        return value_type(0);
    RandomAccessIterator tail=first;
    first+=k;
    value_type window=accumulate(tail,first,value_type(0));
    value_type max_sum=window, current_sum=window;
    while(first!=last)
    {
        window += (*first)-(*tail) ;
        current_sum = max( current_sum+(*first), window );
        max_sum = max(max_sum,current_sum);
        ++first;
        ++tail;
    }
    return max_sum;
}

// __________________________________________________

template<typename E,int N>
E *end(E (&arr)[N])
{
    return arr+N;
}

int main()
{
    using namespace std;
    int arr[]={1,2,4,-5,-4,-3,2,1,5,6,-20,1,1,1,1,1};
    cout << max_subarr_k(arr,end(arr),4) << endl;
    cout << max_subarr_k(arr,end(arr),5) << endl;
}

Output is:

14
11
  int w(0);
    for (int i=0; i < k; i++) w += a[i];
    int run_sum(w), max_sum(w);
    for (int i=k; i < n; i++) {
              w = a[i] + max(w, w-a[i-k]); //  window will such that it will include run_sum
              run_sum = max(run_sum + a[i], w);
              max_sum = max(run_sum, max_sum); 
    }
    return max_sum; 
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