Test for multiple cases in a switch, like an OR (||)

Question

How would you use a switch case when you need to test for a or b in the same case?

switch (pageid) {
  case "listing-page" || "home-page":
    alert("hello");
    break;
  case "details-page":
    alert("goodbye");
    break;
}

Answer 1

You can use fall-through:

switch (pageid)
{
    case "listing-page":
    case "home-page":
        alert("hello");
        break;
    case "details-page":
        alert("goodbye");
        break;
}

Answer 2

Since the other answers explained how to do it without actually explaining why it works:

When the switch executes, it finds the first matching case statement and then executes each line of code after the switch until it hits either a break statement or the end of the switch (or a return statement to leave the entire containing function). When you deliberately omit the break so that code under the next case gets executed too that's called a fall-through. So for the OP's requirement:

switch (pageid) {
   case "listing-page":
   case "home-page":
      alert("hello");
      break;

   case "details-page":
      alert("goodbye");
      break;
} 

Forgetting to include break statements is a fairly common coding mistake and is the first thing you should look for if your switch isn't working the way you expected. For that reason some people like to put a comment in to say "fall through" to make it clear when break statements have been omitted on purpose. I do that in the following example since it is a bit more complicated and shows how some cases can include code to execute before they fall-through:

switch (someVar) {
   case 1:
      someFunction();
      alert("It was 1");
      // fall through
   case 2:
      alert("The 2 case");
      // fall through
   case 3:
      // fall through
   case 4:
      // fall through
   case 5:
      alert("The 5 case");
      // fall through
   case 6:
      alert("The 6 case");
      break;

   case 7:
      alert("Something else");
      break;

   case 8:
      // fall through
   default:
      alert("The end");
      break;
}

You can also (optionally) include a default case, which will be executed if none of the other cases match - if you don't include a default and no cases match then nothing happens. You can (optionally) fall through to the default case.

So in my second example if someVar is 1 it would call someFunction() and then you would see four alerts as it falls through multiple cases some of which have alerts under them. Is someVar is 3, 4 or 5 you'd see two alerts. If someVar is 7 you'd see "Something else" and if it is 8 or any other value you'd see "The end".

Answer 3

You need to make two case labels.

Control will fall through from the first label to the second, so they'll both execute the same code.

Answer 4

You have to switch it!

switch (true) {
    case ( (pageid === "listing-page") || (pageid === ("home-page") ):
        alert("hello");
        break;
    case (pageid === "details-page"):
        alert("goodbye");
        break;
}

Answer 5

Forget switch and break, lets play with if. And instead of asserting

if(pageid === "listing-page" || pageid === "home-page")

lets create several arrays with cases and check it with Array.prototype.includes()

var caseA = ["listing-page", "home-page"];
var caseB = ["details-page", "case04", "case05"];

if(caseA.includes(pageid)) {
    alert("hello");
}
else if (caseB.includes(pageid)) {
    alert("goodbye");
}
else {
    alert("there is no else case");
}

Answer 6

Use commas to separate case

switch (pageid)
{
    case "listing-page","home-page":
        alert("hello");
        break;
    case "details-page":
        alert("goodbye");
        break;
}