static constexpr member of same type as class being defined

问题

I would like a class C to have a static constexpr member of type C. Is this possible in C++11?

Attempt 1:

struct Foo {
    constexpr Foo() {}
    static constexpr Foo f = Foo();
};
constexpr Foo Foo::f;

g++ 4.7.0 says: 'invalid use of incomplete type' referring to the Foo() call.

Attempt 2:

struct Foo {
    constexpr Foo() {}
    static constexpr Foo f;
};
constexpr Foo Foo::f = Foo();

Now the problem is the lack of an initializer for the constexpr member f inside the class definition.

Attempt 3:

struct Foo {
    constexpr Foo() {}
    static const Foo f;
};
constexpr Foo Foo::f = Foo();

Now g++ complains about a redeclaration of Foo::f differing in constexpr.

回答1:

If I interpret the Standard correctly, it isn't possible.

(§9.4.2/3) [...] A static data member of literal type can be declared in the class definition with the constexpr specifier; if so, its declaration shall specify a brace-or-equal-initializer in which every initializer-clause that is an assignment-expression is a constant expression. [...]

From the above (along with the fact that there is no separate statement about non-literal types in static data member declarations), I believe it follows that a static data member that is constexpr must be a literal type (as defined in §3.9/10), and it must have its definition included in the declaration. The latter condition could be satisfied by using the following code:

struct Foo {
  constexpr Foo() {}
  static constexpr Foo f {};
};

which is similar to your Attempt 1, but without the class-external definition.

However, since Foo is incomplete at the time of declaration/definition of the static member, the compiler can't check whether it is a literal type (as defined in §3.9/10), so it rejects the code.

Note that there is this post-C++-11 document (N3308) which discusses various problems of the current definition of constexpr in the Standard, and makes suggestions for amendments. Specifically, the "Proposed Wording" section suggests an amendment of §3.9/10 that implies the inclusion of incomplete types as one kind of literal type. If that amendment was to be accepted into a future version of the Standard, your problem would be solved.

回答2:

I believe GCC is incorrect to reject your Attempt 3. There is no rule in the C++11 standard (or any of its accepted defect reports) which says that a redeclaration of a variable must be constexpr iff the prior declaration was. The closest the standard comes to that rule is in [dcl.constexpr](7.1.5)/1_:

If any declaration of a function or function template has constexpr speciﬁer, then all its declarations shall contain the constexpr speciﬁer.

Clang's implementation of constexpr accepts your Attempt 3.

回答3:

An update on Richard Smith's answer, attempt 3 now compiles on both GCC 4.9 and 5.1, as well as clang 3.4.

struct Foo {
  std::size_t v;
  constexpr Foo() : v(){}
  static const Foo f;
};

constexpr const Foo Foo::f = Foo();

std::array<int, Foo::f.v> a;

However, when Foo is a class template, clang 3.4 fails, but GCC 4.9 and 5.1 still work ok:

template < class T >
struct Foo {
  T v;
  constexpr Foo() : v(){}
  static const Foo f;
};

template < class T >
constexpr const Foo<T> Foo<T>::f = Foo();

std::array<int, Foo<std::size_t>::f.v> a; // gcc ok, clang complains

Clang error :

error: non-type template argument is not a constant expression
std::array<int, Foo<std::size_t>::f.v> a;
                ^~~~~~~~~~~~~~~~~~~~~

来源：https://stackoverflow.com/questions/11928089/static-constexpr-member-of-same-type-as-class-being-defined

标签

c++

c++11

constexpr