xor

问题 My question uses Java as an example, but I guess it applies to probably all. Is there any practical difference between the XOR operator ( ^ in Java) and the not-equal-to operator ( != in Java), when comparing booleans? I evaluated things here, but I just kept wondering (seems weird, two things equal)... and didn't find anything on the net. Just one discussion in some forum that ended quickly without any result. 回答1: For Boolean values, they mean the same thing - although there's a compound

问题 Here is what I read about it but cant understand exactly what it does: One way to implement rubber-banding is to draw in XOR mode. You set XOR mode by calling the setXORMode() method for a graphics context and passing a color to it — usually the background color. In this mode the pixels are not written directly to the screen. The color in which you are drawing is combined with the color of the pixel currently displayed together with a third color that you specify, by exclusive ORing them

问题 I have a string, lets say "123|ABC|test|12345|FF" and I want to xor the ascii value of each character and print the result in hex. What is the simplest way? 回答1: Found it... lrc = 0 input.each_byte do | c | lrc ^= c end hexVal = lrc.to_s(16) 回答2: In Ruby 1.8.7 or 1.9.1: input.bytes.inject { |a,b| a ^ b }.to_s(16) 来源： https://stackoverflow.com/questions/348991/xor-of-string-in-ruby

问题 I have a javascript code: var c = 267414715; var d = c ^ ("0x81BE16CD"); Result is -1907459466 http://jsfiddle.net/4N3JY/1/ I can't seem to get a PHP equivalent. Have tried the following: <?php $c=267414715; $d=$c ^ hexdec("0x81BE16CD"); echo "With hexdec: $d\n"; $d=$c ^ base_convert("0x81BE16CD", 16, 2); echo "With base_convert(2): $d\n"; $d=$c ^ base_convert("0x81BE16CD", 16, 10); echo "With base_convert(10): $d\n"; ?> Output: With hexdec: 2387507830 With base_convert(2):

问题 I have a javascript code: var c = 267414715; var d = c ^ ("0x81BE16CD"); Result is -1907459466 http://jsfiddle.net/4N3JY/1/ I can't seem to get a PHP equivalent. Have tried the following: <?php $c=267414715; $d=$c ^ hexdec("0x81BE16CD"); echo "With hexdec: $d\n"; $d=$c ^ base_convert("0x81BE16CD", 16, 2); echo "With base_convert(2): $d\n"; $d=$c ^ base_convert("0x81BE16CD", 16, 10); echo "With base_convert(10): $d\n"; ?> Output: With hexdec: 2387507830 With base_convert(2):

问题 We have an array A (say [1,2,3]) . We need to find the XOR(^)SUM of all pairs of integers in the array. Though this can easily be done in O(n^2) but how can i improve the complexity of the solution ? E.g for the above array , A, the answer would be (1^2)+(1^3)+(2^3) = 6 Thanks. 回答1: You can separate the calculation to do one bit at a time. For example, look at the rightmost bit of all the numbers in the array. Suppose that a numbers have a rightmost 0-bit, and b numbers have a 1-bit. Then out

问题 how can we XOR hex numbers in python eg. I want to xor 'ABCD' to '12EF'. answer should be B922. i used below code but it is returning garbage value def strxor(a, b): # xor two strings of different lengths if len(a) > len(b): return "".join(["%s" % (ord(x) ^ ord(y)) for (x, y) in zip(a[:len(b)], b)]) else: return "".join(["%s" % (ord(x) ^ ord(y)) for (x, y) in zip(a, b[:len(a)])]) key ='12ef' m1='abcd' print strxor(key,m1) 回答1: Whoa. You're really over-complicating it by a very long distance.

问题 How to do bitwise XOR operation to two strings in java. 回答1: You want something like this: import sun.misc.BASE64Decoder; import sun.misc.BASE64Encoder; import java.io.IOException; public class StringXORer { public String encode(String s, String key) { return base64Encode(xorWithKey(s.getBytes(), key.getBytes())); } public String decode(String s, String key) { return new String(xorWithKey(base64Decode(s), key.getBytes())); } private byte[] xorWithKey(byte[] a, byte[] key) { byte[] out = new

问题 I came across this question in recent interview : Given an array A of length N , we are supposed to answer Q queries. Query form is as follows : Given x and k , we need to make another array B of same length such that B[i] = A[i] ^ x where ^ is XOR operator. Sort an array B in descending order and return B[k] . Input format : First line contains interger N Second line contains N integers denoting array A Third line contains Q i.e. number of queries Next Q lines contains space-separated

问题 Attempting a XOR neural network in java, but the network always predicts the final output it trains in. Here is my code for( int i = 0; i < 4; i++ ) { //Forward pass diff = 1; while( diff > 0.01 ) { SumError = 0; Y1 = ( InputOne[i] * Weight[0] ) + ( InputTwo[i] * Weight[1] ) + Weight[6]; Y1 = 1 / ( 1 + Math.exp( -Y1 ) ); Node1[i] = Y1; Y2 = ( InputOne[i] * Weight[2] ) + ( InputTwo[i] * Weight[3] ) + Weight[7]; Y2 = 1 / ( 1 + Math.exp( -Y2 ) ); Node2[i] = Y2; Y3 = ( Y1 * Weight[4] ) + ( Y2 *