xml.etree

I scrapped some html via xpath, that I then converted into an etree. Something similar to this: <td> text1 <a> link </a> text2 </td> but when I call element.text, I only get text1 (It must be there, when I check my query in FireBug, the text of the elements is highlighted, both the text before and after the embedded anchor elements... Use element.xpath("string()") or lxml.etree.tostring(element, method="text") - see the documentation . As a public service to people out there who may be as lazy as I am. Here's some code from above that you can run. from lxml import etree def get_text1(node):

I am using alexa api from aws but I find difficult in parse the result to get what I want alexa api return an object tree <type 'lxml.etree._ElementTree'> I use this code to print the tree from lxml import etree root = tree.getroot() print etree.tostring(root) I get xml below <aws:UrlInfoResponse xmlns:aws="http://alexa.amazonaws.com/doc/2005-10-05/"><aws:Response xmlns:aws="http://awis.amazonaws.com/doc/2005-07-11"><aws:OperationRequest><aws:RequestId>ccf3f263-ab76-ab63-db99-244666044e85</aws:RequestId></aws:OperationRequest><aws:UrlInfoResult><aws:Alexa> <aws:ContentData> <aws:DataUrl type=

I'm using python version 2.7.3. test.txt: <?xml version="1.0" encoding="UTF-8"?> <root> <test>The tag <StackOverflow> is good to bring up at parties.</test> </root> Result: >>> import xml.etree.ElementTree as ET >>> e = ET.parse('test.txt') >>> root = e.getroot() >>> print root.find('test').text The tag <StackOverflow> is good to bring up at parties. As you can see, the parser must have changed the < 's to < 's etc. What I'd like to see: The tag <StackOverflow> is good to bring up at parties. Untouched, raw text. Sometimes I really like it raw. Uncooked. I'd like to use this text as-is for

I can read tags, except when there is a prefix. I'm not having luck searching SO for a previous question. I need to read media:content . I tried image = node.find("media:content") . Rss input: <channel> <title>Popular Photography in the last 1 week</title> <item> <title>foo</title> <media:category label="Miscellaneous">photography/misc</media:category> <media:content url="http://foo.com/1.jpg" height="375" width="500" medium="image"/> </item> <item> ... </item> </channel> I can read a sibling tag title . from xml.etree import ElementTree with open('cache1.rss', 'rt') as f: tree = ElementTree

How to clone Element objects in Python xml.etree ? I'm trying to procedurally move and copy (then modify their attributes) nodes. You can just use copy.deepcopy() to make a copy of the element. (this will also work with lxml by the way). A different, and somewhat disturbing solution: new_element = lxml.etree.fromstring(lxml.etree.tostring(elem)) At least in Python 2.7 etree Element has a copy method: http://hg.python.org/cpython/file/2.7/Lib/xml/etree/ElementTree.py#l233 It is a shallow copy, but that is preferable in some cases. In my case I am duplicating some SVG Elements and adding a