while-loop

mysqli query results to show all rows

好久不见. 提交于 2019-12-27 11:35:45
问题 I have the following code: include $_SERVER['DOCUMENT_ROOT'].'/include/conn.php'; $query = "SELECT title FROM news_event"; $result = $mysqli->query($query); $row = $result->fetch_array(MYSQLI_BOTH); $row_cnt = $result->num_rows; $result->free(); $mysqli->close(); This is fine if there is only one result as I can just echo $row['title'] but if there are lots of results, how do I get this to loop through and print every row? I'm sure this is really simple but I'm just not sure what I need to

mysqli query results to show all rows

吃可爱长大的小学妹 提交于 2019-12-27 11:32:12
问题 I have the following code: include $_SERVER['DOCUMENT_ROOT'].'/include/conn.php'; $query = "SELECT title FROM news_event"; $result = $mysqli->query($query); $row = $result->fetch_array(MYSQLI_BOTH); $row_cnt = $result->num_rows; $result->free(); $mysqli->close(); This is fine if there is only one result as I can just echo $row['title'] but if there are lots of results, how do I get this to loop through and print every row? I'm sure this is really simple but I'm just not sure what I need to

mysqli query results to show all rows

安稳与你 提交于 2019-12-27 11:32:07
问题 I have the following code: include $_SERVER['DOCUMENT_ROOT'].'/include/conn.php'; $query = "SELECT title FROM news_event"; $result = $mysqli->query($query); $row = $result->fetch_array(MYSQLI_BOTH); $row_cnt = $result->num_rows; $result->free(); $mysqli->close(); This is fine if there is only one result as I can just echo $row['title'] but if there are lots of results, how do I get this to loop through and print every row? I'm sure this is really simple but I'm just not sure what I need to

Java do while loop back to the beginning of application

狂风中的少年 提交于 2019-12-25 21:39:46
问题 This question is a follow-up from this link Java SE do while loop issues This is an application asking for a room's name then second prompt to ask for its dimensions to perform some calculations. right after everything has been done, the application should be able to return back to the first prompt asking for the name of room etc. class Room { private String name; private double length; private double width; private double height; public Room(String r, double l, double w, double h) { name = r

Java do while loop back to the beginning of application

帅比萌擦擦* 提交于 2019-12-25 21:38:11
问题 This question is a follow-up from this link Java SE do while loop issues This is an application asking for a room's name then second prompt to ask for its dimensions to perform some calculations. right after everything has been done, the application should be able to return back to the first prompt asking for the name of room etc. class Room { private String name; private double length; private double width; private double height; public Room(String r, double l, double w, double h) { name = r

While loop only displaying one row

隐身守侯 提交于 2019-12-25 19:15:10
问题 I have an HTML form that allows the user to select from a list of employees. The variable is '$empfullname.' However, I also want them to be able to select an 'All' option and if selected it should take the first employee and run the PHP script, then take the next, and so on and so forth. However, the code I have right now if 'All' is selected just displays the first employee in the table and stops. Maybe I need a foreach in their as well? Any help is greatly appreciated. Thanks. if (

php while loop running only once

陌路散爱 提交于 2019-12-25 19:05:34
问题 I have a php script for check the availability of some data. I call this script from external jquery. the jquery is running fine. here is my php: <?php $avares = checkAva($fi_nm, $tbl_nm, $txtval); echo $avares; function checkAva($field, $table, $curval) { $avres = mysql_query("SELECT " . $field . " FROM " . $table . "") or die("query failed"); while ($a_row = mysql_fetch_array($avres)) { $dbval = $a_row[$field]; if ($curval == $dbval) { return "no"; } else { return "yes"; } } } ?> $curval is

Python variable increment while-loop

纵饮孤独 提交于 2019-12-25 18:59:28
问题 I'm trying to make the variable number increase if user guessed the right number! And continue increase the increased one if it is guessed by another user. But it's seem my syntax is wrong. So i really need your help. Bellow is my code: #!/usr/bin/python # Filename: while.py number = 23 running = True while running: guess = int(raw_input('Enter an integer : ')) if guess == number: print 'Congratulations, you guessed it. The number is now increase' number += 1 # Increase this so the next user

count between 2 inputted numbers (range) & display each

不想你离开。 提交于 2019-12-25 18:34:47
问题 My attempt is below; to first start with a while loop to create the array, then iterate through each with a foreach in attempt to count each item in array. $begin = $_POST['startpoint']; $end = $_POST['endpoint']; $current_start = $begin; $num1 = 3; $num2 = 355; while ($i = $begin; $i <= $end; ++$i) { $array[] = $i; foreach ($array as &$counted) { echo '<span>Star SC ' + $counted + ' mag ' + $num1 + $num2; } } the desired output would be something like this; if user inserted say 10002 and

getting error while installing opencv via pip

怎甘沉沦 提交于 2019-12-25 18:27:07
问题 python version = Python 3.8.0 pip version = 19.3.1 C:\Users\Sami Ullah Ch>pip3 install opencv-python ERROR: Could not find a version that satisfies the requirement opencv-python (from versions: none) 回答1: Install OpenCV Refresh the packages index and install the OpenCV package by typing: sudo apt update sudo apt install python3-opencv The command above will install all packages necessary to run OpenCV. Verify the OpenCV installation To verify the installation we will import the cv2 module and