while-loop

问题 #Program to print fibonacci until a range. print "Fibonacci Series" print "Enter a range" range = raw_input() first=1 second =1 print first print ", " print second print ", " third = 0 while(third < range): third=first+second print third print ", " first = second second = third #End of program Here, the program asks user for a range and prints the series upto the range. But, m getting the series of infinite loop. Can anyone help me? 回答1: range = raw_input() sets range to be a string , e.g. it

问题 Afternoon all. The code below works perfectly, however, I need to pull each row of the php sql array out and into the script var. Any ideas on how to write a while loop that could do this? Thanks for any help var enableDays = ["<?php echo mysql_result($result, 0, 'date'); ?>"]; enableDays.push("<?php echo mysql_result($result, 1, 'date'); ?>"); Additional Code:: $rows = array(); while ($row = mysql_fetch_assoc($result)) { $rows[] = $row; } var enableDays = [<?php echo json_encode($rows); ?>];

问题 This question already has answers here : Asking the user for input until they give a valid response (19 answers) How to let a raw_input repeat until I want to quit? (4 answers) Closed 4 years ago . I am attempting to make my program repeat when the user inputs y/n, however I am confused on how to use a while true with this type of input, below is some code. again = input("Would you like to play again? enter y/n: ") if again == "n": print ("Thanks for Playing!") quit if again == "y": print (

问题 i have something like while(playAgain==true) { cout<<"new game"<<endl; //i know 'using namespace std;' is looked down upon while(playerCard!=21) { *statements* if(decision=='n') { break } ... } } but that break only breaks out of the first while loop when I want to break out of both of the loops 回答1: Don't cook spaghetti and extract your loops into the function: void foo(...) { while (...) { /* some code... */ while (...) { if ( /* this loop should stop */ ) break; if ( /* both loops should

问题 When I use an Iterator of Object I use a while loop (as written in every book learning Java, as Thinking in Java of Bruce Eckel): Iterator it=... while(it.hasNext()){ //... } but sometime i saw than instead somebody use the for loop : Iterator it=... for (Iterator it=...; it.hasNext();){ //... } I don't' understand this choice: I use the for loop when I have a collection with ordinal sequence (as array) or with a special rule for the step (declared generally as a simple increment counter++ ).

问题 Correct me if I'm wrong, but when I try to update my label in a while loop it won't update it. Is the reason that the while loop runs too quickly for the label to update within that time so it'll cancel the label from updating? I need a solution to this? I need to be able to update the label straight away? func Download(complete: (canMoveOn: Bool) -> Void) { isDownload = true if (connected!) { Reset() let data = NSData(contentsOfFile: path!)! let buffer = (UnsafeMutablePointer<UInt8>(data

问题 Correct me if I'm wrong, but when I try to update my label in a while loop it won't update it. Is the reason that the while loop runs too quickly for the label to update within that time so it'll cancel the label from updating? I need a solution to this? I need to be able to update the label straight away? func Download(complete: (canMoveOn: Bool) -> Void) { isDownload = true if (connected!) { Reset() let data = NSData(contentsOfFile: path!)! let buffer = (UnsafeMutablePointer<UInt8>(data

问题 What would a very simple while loop statement be that would continue the below program until the user types "exit"? For example, while response = (!'exit') continue file else break print ('Thank you, good bye!') #I know this is completely wrong, but it's a try! My file so far: #!/usr/bin/python friends = {'John' : {'phone' : '0401', 'birthday' : '31 July', 'address' : 'UK', 'interests' : ['a', 'b', 'c']}, 'Harry' : {'phone' : '0402', 'birthday' : '2 August', 'address' : 'Hungary', 'interests'

问题 What would a very simple while loop statement be that would continue the below program until the user types "exit"? For example, while response = (!'exit') continue file else break print ('Thank you, good bye!') #I know this is completely wrong, but it's a try! My file so far: #!/usr/bin/python friends = {'John' : {'phone' : '0401', 'birthday' : '31 July', 'address' : 'UK', 'interests' : ['a', 'b', 'c']}, 'Harry' : {'phone' : '0402', 'birthday' : '2 August', 'address' : 'Hungary', 'interests'

问题 /// infinite loop?? $x=1; while($x=9){ echo $x; $x++; } i dont understand the reason behind, why the above code causes infinite loop in my opinion above code should output "9" once. but it outputs endless 999999999...... at first (when x is equal to 1) while statement is false so nothing happens, then x becomes 2 but again while statement is false; So when x becomes 9 while statement is true so it should echo 9 then we add 1 due to x++; and it becomes 10 so while statement becomes false but