wait

casper.test.begin('Test foo', 1, function suite(test) { casper.start("http://www.foo.com", function() { casper.waitForResource("bar", function(resource) { casper.echo(resource.url); }); }); casper.run(function() { test.done(); }); }); casper.echo returns www.foo.com resource (the one in casper.start ), not the one with "bar". How can I get the resource i've waited for with waitForResource ? You actually waited for the "bar" resource. The problem is that resource inside the then callback function of waitForResource is actually the page resource of the last start or open ( thenOpen ) call. It

I'm trying to display a sort of loading animation, specifically three dots appearing over and over. I thought the below would work: import time, sys for i in range(9): time.sleep(0.2) x = i % 4 sys.stdout.write("." * x) sys.stdout.flush() However all it does is just gradually (and non-uniformly) load this: "........." Use \r the return character. This is because your cursor should return to the original position after you lapse the time import time, sys for i in range(15): sys.stdout.write(" ") x = i % 4 sys.stdout.write('\r' + "." * x ) time.sleep(0.5) sys.stdout.flush() 来源： https:/

I have been trying to solve a problem involving thread communication using wait() and notify(). Basically i have 2 threads T1 and T2 and i want them to be executed in the following order T1 , T2, T1, T2 ..... How can i achieve that? Actual Problem: There are 2 threads T1 - which prints odd numbers (say 1 - 100) and T2 - which prints even numbers (1 - 100). Now, the output should be 1, 2, 3, 4 , 5 , .... 100 You describe a Producer-Consumer pattern. It's java implementations described in numerous java books including M.Grand "Patterns in Java. Volume I" and "Java 2: The Complete Reference" by

I have a Bash script (Bash 3.2, Mac OS X 10.8) that invokes multiple Python scripts in parallel in order to better utilize multiple cores. Each Python script takes a really long time to complete. The problem is that if I hit Ctrl+C in the middle of the Bash script, the Python scripts do not actually get killed. How can I write the Bash script so that killing it will also kill all its background children? Here's my original "reduced test case". Unfortunately I seem to have reduced it so much that it no longer demonstrates the problem; my mistake. set -e cat >work.py <<EOF import sys, time for i

Is there any way to make PHP wait until a function returns before continuing? This is my code: <?php set_time_limit(0); function waitforchange($nof) { $lfilemod=filemtime($nof); while(filemtime($nof) == $lfilemod) { clearstatcache(); usleep(10000); } } waitforchange('./blahblah.txt') sleep(5); echo 'done'; ?> It is supposed to wait until blahblah.txt changes, wait another five seconds after that, then print out "done", however, it prints out "done" after five seconds, regardless whether the file actually changed. PHP is single-threaded, which means that it executes one instruction at a time

Say I want to draw a line, then wait five seconds, then draw another line. I have a method like this: public void onDraw(Canvas canvas) { int w = canvas.getWidth(); int h = canvas.getHeight(); canvas.drawLine(w/2, 0, w/2, h-1, paint); // PAUSE FIVE SECONDS canvas.drawLine(0, h/2, w-1, h/2, paint); } How do I pause? Don't wait in onDraw method it's called in the UI thread and you'll block it. Use flags to handle which line will be drawn boolean shouldDrawSecondLine = false; public void setDrawSecondLine(boolean flag) { shouldDrawSecondLine = flag; } public void onDraw(Canvas canvas) { int w =