wait

Using JavaFX 8.0 and JRE 1.8.0 u45 in IntelliJ, I created a basic pixel editor app. I have two windows(stages). One is a 32x128 matrix of Circle Objects placed in a Grid Pane and the other, a Tools widow; I have one Controller.java . Using the mouse, the Tools window provides tools to draw lines, rectangles, etc. and a menu for Setup, Files and Playlists. The Files menu presents the user with Open, SaveAs and Delete. To view a saved pixel art file, the user clicks Open and via the JFileChooser , the selected file is opened and each Circle’s assigned color is displayed using the following

I was wondering if you guys could help me out. I'm trying to make an animation program with Java's built in graphics module... The thing is, Java executes everything at once; there isn't any time between the different animations. The end product is just the last picture. I need a function that puts like half a second in between each of the pictures. Any help is appreciated. Specs: Blue-J, JDK 6. Edit: Btw, I'm a Java Newbie, and this is a class thing. The assignment was to make an animation, and press 'c' to go forward each frame, but I think thats kinda ghetto, so I want something better.

线程是操作系统中独立的个体，如果不经过处理就不能成为一个整体。使线程进行通信后，系统之间的交互性会更强大，在大大提高CPU利用率的同时还能够对个线程任务在处理过程中进行有效的把控和监督。 等待/通知机制 首先看一下一个不用等待/通知机制实现线程间通信的例子，使用sleep结合while（true）死循环来实现. public class MyList { private List list = new ArrayList(); public void add(){ list.add(" "); } public int size() { return list.size(); } } public class ThreadA extends Thread { MyList myList; public ThreadA(MyList list){ this.myList= list; } public void run(){ for(int i= 0; i < 10; i ++){ myList.add(); ThreadA.sleep(1000); } } } public class ThreadB extends Thread { MyList myList; public ThreadB(MyList list){ this.myList= list; } public

在多线程的情况下，由于同一进程的多个线程共享同一片存储空间，在带来方便的同时，也带来了访问冲突这个严重的问题。Java语言提供了专门机制以解决这种冲突，有效避免了同一个数据对象被多个线程同时访问。 wait与notify是java同步机制中重要的组成部分。结合与synchronized关键字使用，可以建立很多优秀的同步模型。 synchronized(this){ }等价于publicsynchronized void method(){.....} 同步分为类级别和对象级别，分别对应着类锁和对象锁。类锁是每个类只有一个，如果static的方法被synchronized关键字修饰，则在这个方法被执行前必须获得类锁；对象锁类同。 首先，调用一个Object的wait与notify/notifyAll的时候，必须保证调用代码对该Object是同步的，也就是说必须在作用等同于synchronized(obj){......}的内部才能够去调用obj的wait与notify/notifyAll三个方法，否则就会报错： java.lang.IllegalMonitorStateException:current thread not owner 在调用wait的时候，线程自动释放其占有的对象锁，同时不会去申请对象锁。当线程被唤醒的时候，它才再次获得了去获得对象锁的权利。 所以

Java是第一个内置对多线程支持的主流编程语言。在Java5之前，对多线程的支持主要是通过对块结构的同步实现的（synchronized配合wait，notify，notifyAll），Java5引入了java.util.concurrent包，提供了对多线程编程的更高层的支持。 在Java中，除了int等基本类型之外，一切皆为对象。synchronized关键字以及Object类中的wait，notify和notifyAll方法为我们编写多线程程序提供了原始的支持。 例如： public class A { public synchronized void fun() { ... } } 在调用方法fun之前，调用该方法的执行线程必须要先获得类A的实例（a）的对象锁。上面的方法fun在功能上等同于： public void fun() { synchronized(this) { ... } } 在执行fun之前，要获取a的对象锁，在方法fun返回之前，要释放a的对象锁。 通常可以使用synchronized和notify，notifyAll以及wait方法来实现线程之间的数据传递及控制。对于对象obj来说： obj.wait()：该方法的调用，使得调用该方法的执行线程（T1）放弃obj的对象锁并阻塞，直到别的线程调用了obj的notifyAll方法

I have a script that uses sed to search and replace a simple .yaml file and output a .sh file which should then be pulled in with source. My problem is that I can't figure out how to wait until sed outputs the .sh before calling source . sed -e 's/:[^:\/\/]/="/g;s/$/"/g;s/ *=/=/g' in.yaml > out.sh source out.sh EDIT I get this error script.sh: line 2: out.sh: No such file or directory END EDIT I've tried sed -e 's/:[^:\/\/]/="/g;s/$/"/g;s/ *=/=/g' in.yaml > out.sh wait $! source out.sh , but I believe that this requires the process to be in the bg. I tried throwing it in the bg, but I get the

I am new to processes in linux and c. I am using this straightforward example: #include <stdio.h> #include <stdlib.h> #include <unistd.h> int main(int argc, const char * argv[]) { pid_t child_pid_or_zero = fork(); //fork returns twice if(child_pid_or_zero < 0) { //if fork returns a number smaller than zero, something wrong happened perror("Something wrong happened\n"); exit(-1); } if(child_pid_or_zero > 0) { //if fork returns a number greater than zero, this is the parent process printf("I'm the parent, my pid is: %d\t My child pid is %d\n", getpid(), child_pid_or_zero); wait(NULL); } else { /

Here's the scenario I have an activity(A) which has a button and textview. I have another class(B) with methods for performing various functions. After creating an instance of class B, one of it's public method is called from A when the button is clicked. The method takes a while to execute(it invokes another time consuming private methods in the class) and returns the value of one of the private members of class B. The trouble is that the method returns the initial value of the member and not the values after computation. Is there way to force the function to wait for some time and return the

I would like when my app starts for it to show an Alert view for about 5 seconds, then depending on the outcome of a background process, it will show another Alert view. The problem I am experiencing is that when I try to use Sleep to wait for a background process to occur. The first Alert does not show and wait the 5 seconds. The app shows the first view of the app, and then after 5 seconds the first Alert shows briefly. What do I need to do to perform what I wish. Here is my code. - (void)viewDidAppear:(BOOL)animated { SSGlobalSettings *connSettings = [SSGlobalSettings sharedManager];