void-pointers

I have a C++ program: struct arguments { int a, b, c; arguments(): a(3), b(6), c(9) {} }; class test_class{ public: void *member_func(void *args){ arguments vars = (arguments *) (*args); //error: void is not a //pointer-to-object type std::cout << "\n" << vars.a << "\t" << vars.b << "\t" << vars.c << "\n"; } }; On compile it throws an error: error: ‘void*’ is not a pointer-to-object type Can someone explain what I am doing wrong to produce this error? You are dereferencing the void * before casting it to a concrete type. You need to do it the other way around: arguments vars = *(arguments *)

I am trying to understand what this means, the code I am looking at has in .h typedef void (*MCB)(); static MCB m_process; in .C MCB Modes::m_process = NULL; And sometimes when I do m_process(); I get segmentations fault, it's probably because the memory was freed, how can I debug when it gets freed? I hope my questions are clear. It defines a pointer-to-function type. The functions return void, and the argument list is unspecified because the question is (currently, but possibly erroneously) tagged C; if it were tagged C++, then the function would take no arguments at all. To make it a

Possible Duplicate: What is a void pointer and what is a null pointer? I often see code which resembles something like the following: void * foo(int bar); What does this mean? Does it mean that it can return anything ? Is this similar to dynamic or object in C#? A void* does not mean anything. It is a pointer, but the type that it points to is not known. It's not that it can return "anything". A function that returns a void* generally is doing one of the following: It is dealing in unformatted memory. This is what operator new and malloc return: a pointer to a block of memory of a certain size