uuid

Android: How do bluetooth UUIDs work?

匿名 (未验证) 提交于 2019-12-03 02:11:02
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: I don't understand what a bluetooth UUID denotes. Do UUIDs denote protocols (e.g. RFCOMM )? If so, why do the createRfcommSocketToServiceRecord() methods require UUIDs, when they specify rfcomm right in their names? Why does the BluetoothChat sample code have a seemingly arbitrary, hardcoded UUID? My question arises because, as per this question , I'm getting a null pointer exception when devices running 4.0.4 try to connect (to an external, non-android device) using reflection. However, the solution to that question doesn't work for me.

iOS unique user identifier [duplicate]

匿名 (未验证) 提交于 2019-12-03 02:11:02
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: This question already has an answer here: UIDevice uniqueIdentifier Deprecated - What To Do Now? 33 answers I'm writting an application for iphone, which communicates with my server using REST. The main problem is, I need to identify user somehow. Not so long ago, we were allowed to use UDID, but now its not allowed anymore. So what should I use instead? I need some kind of identifier on iphone, so user will delete application, install it again, and he will get same id. 回答1: Firstly, the UDID is only deprecated in iOS 5. That doesn't mean it

IOException: read failed, socket might closed - Bluetooth on Android 4.3

匿名 (未验证) 提交于 2019-12-03 02:08:02
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: Currently I am trying to deal with a strange Exception when opening a BluetoothSocket on my Nexus 7 (2012), with Android 4.3 (Build JWR66Y, I guess the second 4.3 update). I have seen some related postings (e.g. https://stackoverflow.com/questions/13648373/bluetoothsocket-connect-throwing-exception-read-failed ), but none seems to provide a workaround for this issue. Also, as suggested in these threads, re-pairing does not help, and constantly trying to connect (through a stupid loop) also has no effect. I am dealing with an embedded device

How to get POSTed json in Flask?

匿名 (未验证) 提交于 2019-12-03 02:08:02
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 由 翻译 强力驱动 问题: I'm trying to build a simple API using Flask, in which I now want to read some POSTed JSON. I do the post with the PostMan Chrome extension , and the JSON I post is simply {"text":"lalala"} . I try to read the JSON using the following method: @app . route ( '/api/add_message/<uuid>' , methods =[ 'GET' , 'POST' ]) def add_message ( uuid ): content = request . json print content return uuid On the browser it correctly returns the uuid I put in the GET, but on the console, it just prints out None (where I expect it to print out the {

Can&#039;t use uuid and create an extension to use it

匿名 (未验证) 提交于 2019-12-03 02:05:01
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: I want to use uuid in Postgresql 9.2 on Ubuntu 13. So when I tried to check whether is available or not, I did: select uuid_generate_v4() as one; And it gave me ERROR: function uuid_generate_v4() does not exist Then I did CREATE EXTENSION "uuid-ossp"; ERROR: could not open extension control file "/usr/share/postgresql/9.2/extension/uuid-ossp.control": No such file or directory Well, what do I do next? By the way, SELECT * FROM pg_available_extensions; returns plpsql (1.0) only. 回答1: The operating system package that contains the extension is

sqlalchemy: alembic bulk insert fails: &#039;str&#039; object has no attribute &#039;_autoincrement_column&#039;

匿名 (未验证) 提交于 2019-12-03 02:03:01
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: My model looks like class Category(UserMixin, db.Model): __tablename__ = 'categories' uuid = Column('uuid', GUID(), default=uuid.uuid4, primary_key=True, unique=True) name = Column('name', String, nullable=False) parent = Column('parent', String, nullable=False) created_on = Column('created_on', sa.types.DateTime(timezone=True), default=datetime.utcnow()) __table_args__ = (UniqueConstraint('name', 'parent'),) def __init__(self, name, parent): self.name = name self.parent = parent def __repr__(self): return ' ' % ( self.uuid, self.name, self

What kind of data can you extract from a UUID?

会有一股神秘感。 提交于 2019-12-03 02:01:43
问题 I know that we could easily extract the uuid version number. Is there a reliable way to extract information like timestamp, MAC address? Thanks! 回答1: A standard-conforming UUID may be one of several variants, it looks like this: AAAAAAAA-BBBB-CCCC-DDDD-FFFFFFFFFFFF The first (hex)digit of the DDDD part determines the variant. If it is one of 8,9,A,B it is conforming to the current spec (0-7 are reserved for backward compatibility, C,D are reserved for Microsoft, and E,F are reserved for

Generating a unique ID in PHP

核能气质少年 提交于 2019-12-03 01:59:15
I'm trying to generate a unique ID in php in order to store user-uploaded content on a FS without conflicts. I'm using php, and at the moment this little snippet is responsible for generating the UID: $id = tempnam (".", ""); unlink($id); $id = substr($id, 2); This code is hideous: it creates a temporary file on the FS and deletes it, retaining only the relevant unique part of the generated string. Is there any better way to do this, most preferably without any external dependencies? Thanks much! string uniqid ([ string $prefix [, bool $more_entropy ]] ) Gets a prefixed unique identifier based

Extract the time from a UUID v1 in python

匿名 (未验证) 提交于 2019-12-03 01:59:02
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: I have some UUIDs that are being generated in my program at random, but I want to be able to extract the timestamp of the generated UUID for testing purposes. I noticed that using the fields accessor I can get the various parts of the timestamp but I have no idea on how to combine them. 回答1: Looking inside /usr/lib/python2.6/uuid.py you'll see def uuid1(node=None, clock_seq=None): ... nanoseconds = int(time.time() * 1e9) # 0x01b21dd213814000 is the number of 100-ns intervals between the # UUID epoch 1582-10-15 00:00:00 and the Unix epoch

How to create a GUID/UUID in Python

匿名 (未验证) 提交于 2019-12-03 01:59:02
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 由 翻译 强力驱动 问题: How do I create a GUID in Python that is platform independent? I hear there is a method using ActivePython on Windows but it's Windows only because it uses COM. Is there a method using plain Python? 回答1: "The uuid module, in Python 2.5 and up, provides RFC compliant UUID generation. See the module docs and the RFC for details." Docs: Python 2: http://docs.python.org/2/library/uuid.html Python 3: https://docs.python.org/3/library/uuid.html Example (working on 2 and 3): >>> import uuid >>> uuid . uuid4 () UUID ( 'bd65600d-8669-4903