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Django sending emails with links

由 删除回忆录丶 提交于 2021-01-03 06:42:53
问题 I have a sending code: def send_email(site_id, email): subject = "Sub" from_email, to = EMAIL_FROM, email text_content = 'Text' html_content = render_to_string( 'app/includes/email.html', {'pk': site_id} ) msg = EmailMultiAlternatives(subject, text_content, from_email, [to]) msg.attach_alternative(html_content, "text/html") msg.send() And in my template <!DOCTYPE html> <html lang="en"> <head> <meta charset="UTF-8"> <title>title</title> </head> <body> <a href="{% url 'mail_view' pk %}">Click<

Why does Django's URLField truncate to 200 characters by default?

由 一曲冷凌霜 提交于 2021-01-03 06:36:50
问题 I'm fond of Django and use it regularly. I find most of its defaults sane, but one has always bothered me to the point that I override it on every project. The default max length of a URLField model field is 200 characters. The docs verify this limit, but don't explain why it is the case. class URLField(CharField): ... def __init__(self, verbose_name=None, name=None, **kwargs): kwargs['max_length'] = kwargs.get('max_length', 200) ... I override it because plenty of URLs are longer than 200

Google News XML API: use country/language parameters

由 爱⌒轻易说出口 提交于 2021-01-03 04:16:30
问题 I would like to subscribe to an RSS/XML feed from Google News that captures the following query: Articles mentioning "studie" (German for "study"), written in German, emanating from any country. I'm using https://news.google.com/rss/search, but for this example, it's easier to see the UI output at https://news.google.com/search, so I'll use the latter URL base in this example. Now, in the XML API reference, Google mentions four different parameters that influence either language or country:

Google News XML API: use country/language parameters

由 无人久伴 提交于 2021-01-03 04:15:07
问题 I would like to subscribe to an RSS/XML feed from Google News that captures the following query: Articles mentioning "studie" (German for "study"), written in German, emanating from any country. I'm using https://news.google.com/rss/search, but for this example, it's easier to see the UI output at https://news.google.com/search, so I'll use the latter URL base in this example. Now, in the XML API reference, Google mentions four different parameters that influence either language or country:

Dynamically add query parameters without value to Retrofit request

由 穿精又带淫゛_ 提交于 2021-01-02 05:00:06
问题 I have request that set list of services that are turned on for user. Request has following format: https://myserver.com/setservices?param1=val1&param2=val2&service[10]&service[1000]&service[10000] List of service parameters ("service[10]&service[1000]&service[10000]") is created dynamically and each parameter doesn't have value. Is it possible to achive this using Retrofit? 回答1: From the retrofit documentation: For complex query parameter combinations a Map can be used. @GET("/group/{id}

How does `#:~:text=` in URL works to highlight text?

由 白昼怎懂夜的黑 提交于 2020-12-30 01:33:45
问题 TL;DR How/why are some browsers able to search and highlight text in the HTML body which is followed by #:~:text= in the URL? Explanation One day I was searching for something on Google, which lead me to Quora's result. I observed that 2 sentences were highlighted in yellow, which were part of URL after the aforementioned parameter. I thought this would be Quora's feature for SEO or something, however, also found this on Linkedin, and Medium, and so on. I'd like to know: What is this

How can I get current base URI in flask? [duplicate]

由 烂漫一生 提交于 2020-12-29 06:11:37
问题 This question already has answers here : How do I get the different parts of a Flask request's url? (4 answers) Closed 3 years ago . In below code, i want to store URL in a variable to check error on which URL error occured. @app.route('/flights', methods=['GET']) def get_flight(): flight_data= mongo.db.flight_details info = [] for index in flight_data.find(): info.append({'flight_name': index['flight_name'], 'flight_no': index['flight_no'], 'total_seat': index['total_seat'] }) if request

How can I get current base URI in flask? [duplicate]

由 会有一股神秘感。 提交于 2020-12-29 06:07:52
问题 This question already has answers here : How do I get the different parts of a Flask request's url? (4 answers) Closed 3 years ago . In below code, i want to store URL in a variable to check error on which URL error occured. @app.route('/flights', methods=['GET']) def get_flight(): flight_data= mongo.db.flight_details info = [] for index in flight_data.find(): info.append({'flight_name': index['flight_name'], 'flight_no': index['flight_no'], 'total_seat': index['total_seat'] }) if request

XML::LibXML issue finding XML nodes with a namespace

由 被刻印的时光 ゝ 提交于 2020-12-26 08:21:26
问题 I am writing an XML parser and am having an issue with the program handling a link. I am attempting to parse an XML hierarchy Settings/Setting then findnode 'Value'. The following is an example of the XML: <?xml version='1.0' ?> <Settings xmlns='http://hme.com/Settings.xsd'> <Setting SID="0"> <Name>Store ID</Name> <Value>72</Value> </Setting> <Setting SID="1"> <Name>Deprecated</Name> <Value>0</Value> </Setting> <Setting SID="8"> <Name>Open Store Hours Sunday</Name> <Value>25200</Value> <

Vue.js: How to prevent browser from going to href link and instead only execute the @click method?

由 坚强是说给别人听的谎言 提交于 2020-12-25 06:13:42
问题 So I have a link in my application like this: <a href="/threads/my-first-thread/" @click="openThread">My first thread</a> At the moment, when I click the link, the browsers follows the href link and also executes the "openThread" method. I want to keep the link in there so that it shows the user where a click is going to bring him to, but I don't want the browser to actually follow the link (I open a lightbox instead and change the url with pushState). I want it to only execute the given
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