问题
In below code, i want to store URL in a variable to check error on which URL error occured.
@app.route('/flights', methods=['GET'])
def get_flight():
flight_data= mongo.db.flight_details
info = []
for index in flight_data.find():
info.append({'flight_name': index['flight_name'], 'flight_no': index['flight_no'], 'total_seat': index['total_seat'] })
if request.headers['Accept'] == 'application/xml':
template = render_template('data.xml', info=info)
xml_response = make_response(template)
xml_response.headers['Accept'] = 'application/xml'
logger.info('sucessful got data')
return xml_response
elif request.headers['Accept'] == 'application/json':
logger.info('sucessful got data')
return jsonify(info)
Output:
* Restarting with stat
* Debugger is active!
* Debugger PIN: 165-678-508
* Running on http://127.0.0.1:5000/ (Press CTRL+C to quit)
127.0.0.1 - - [28/Mar/2017 10:44:53] "GET /flights HTTP/1.1" 200 -
I want this message
"127.0.0.1 - - [28/Mar/2017 10:44:53] "GET /flights HTTP/1.1" 200 -"
should be stored in a variable or how can I get current URL that is executing?
回答1:
You can use the base_url
method on flask's request
function.
from flask import Flask, request
app = Flask(__name__)
@app.route('/foo')
def index():
return request.base_url
if __name__ == '__main__':
app.run()
This returns the following if the app route is /foo
:
http://localhost:5000/foo
回答2:
Use flask.request.url
to retrieve your requested url. Have a look at: http://flask.pocoo.org/docs/1.0/api/#flask.Request (or the v0.12 docs)
来源:https://stackoverflow.com/questions/43062047/how-can-i-get-current-base-uri-in-flask