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问题 I'm sending a JSON object to ruby with javascript. But I cannot parse it in there. I tried following stuff but no luck. Also I've been searching around for while now, but I couldn't find anything helpful. Note that I'm very new ruby. My trials: def initialize(game_conf_json) parsed_conf = JSON.parse(conf_json) @param1 = parsed_conf['name'][0] @param2 = parsed_conf['surname'][0] =begin I also tried this: @param1 = parsed_conf['name'] @param2 = parsed_conf['surname'] But no matter what other

问题 I have a url http://www.example.com/state=survey&action=display&survey=39&zone=surveys&currency=Denmark A user will land on a new page with the above url. This page will include a form. There is an input with an id 'currencyrequired' - i want this input to automatically pull in the currency variable from the url (in this example Denmark). <input type="text" id="currencyrequired" name="currencyrequired" size="40" maxlength="20" value="" class="input-pos-int"> The currency part of the url is

问题 I have a website, www.a.com In that website, I serve a page at https://www.a.com/mypage that contains this: <script src='https://www.b.com/anotherpage'></script> If I visit from every browser, b.com will receive this as http referrer: https://www.a.com/mypage However, if I visit from Safari mobile or desktop, the referrer becomes: https://www.a.com/ Why? How can I force Safari to send the full referrer? Example: from Safari, b.com logs: 123.45.678.901 - - [06/Jun/2020:00:32:03 +0200] "GET

问题 My question is closely related to this one Rails friendly id with non-Latin characters. Following the suggested answer there, I implemented a little bit different solution (I know, it's primitive, but I just want to make sure it works before adding complex behavior). In my user model I have: extend FriendlyId friendly_id :slug_candidates, :use => [:slugged] def slug_candidates [ [:first_name, :last_name], [:first_name, :last_name, :uid] ] end def should_generate_new_friendly_id? first_name

问题 I have a website, www.a.com In that website, I serve a page at https://www.a.com/mypage that contains this: <script src='https://www.b.com/anotherpage'></script> If I visit from every browser, b.com will receive this as http referrer: https://www.a.com/mypage However, if I visit from Safari mobile or desktop, the referrer becomes: https://www.a.com/ Why? How can I force Safari to send the full referrer? Example: from Safari, b.com logs: 123.45.678.901 - - [06/Jun/2020:00:32:03 +0200] "GET

问题 Linking to a specific part of a web page and Is there any way to bookmark or link to a section of a page without an anchor? have answers/comments that say that linking to a particular part of a page cannot be done unless that page has addressable items in it such as anchors. But I'm really needing this for research: I need to paste URLs to any arbitrary section in any arbitrary page without requiring that page to have anchors (e.g., I would like a URL that essentially goes to http://www.zdnet

问题 I'm in the process of overhauling one of my projects, a web based booking system, but I'm having a bit of an issue with my htaccess file. The old system was pretty standard, with .php scripts in the route of the website, I had a rule hiding my extensions, and I resultantly had a URL like /viewinvoce?ID=1. I've been trying to find out how to rewrite this URL so it looks a lot neater - in the format /viewinvoice/1, and I'm getting there, but I have a slight problem... The URL /test works - it

问题 An API I work with provides URL links, that can contain special characters like "http://es.dbpedia.org/resource/Análisis_de_datos" (the letter " á " inside). It's an absolutely valid URL, however, if a decodable class contains an optional URL? variable, it can't be decoded. I can change URL? to String? in my class and have a computed variable with something like URL(string: urlString.addingPercentEncoding(withAllowedCharacters: .urlFragmentAllowed) but perhaps there is a more elegant solution

问题 I am attempting to get the Android application chooser to launch when a specific URL is clicked from within a registration e-mail. I have already looked at the below question and several others but I am still having no luck with this. Launching Android Application from link or email I have created my intent in the AndroidManifest.xml file as below (I've placed my website address where you see ".website.org"): <activity android:name=".MainActivity" android:configChanges="orientation|screenSize

问题 In the following URL, that unsubscribes a user from a list: http://xxxxx.us2.list-manage.com/unsubscribe? u=87f537bccxx35e53a1890e0d9& id=40dcxx6cd6& e=c4aaxx1dd6& c=9a6xx11963 What does each parameter do? 回答1: Today I had to learn what each nondescript parameter means so that I could generate URLs for each email I send through Mandrill. It wasn't that easy to discover their meaning, but here are the one's I've come up with and how I found out what they are. http://xxxxx.us2.list-manage.com