url

问题 I want to get image url from array. $img_link = "http://testserver1.com:8080/test%20messages%20and%20so%20on<br /><br /><div style="text-align: center"><img width="396" height="342" src="http://testserver2.com/photos/5186145181.jpg" alt="" style="border: medium none" /></div><br />test messages and so on <br /><br />" I want to grab image url "http://testserver2.com/photos/5186145181.jpg", and put this into "img_link_results". $img_linkA = explode(' ', $img_link); $img_link_results = array();

问题 I am trying to create a list of URLs using a for loop. It prints all the correct URLs, but is not saving them in a list. Ultimately I want to download multiple files using urlretrieve. for i, j in zip(range(0, 17), range(1, 18)): if i < 8 or j < 10: url = "https://Here is a URL/P200{}".format(i) + "-0{}".format(j) + ".xls" print(url) if i == 9 and j == 10: url = "https://Here is a URL/P200{}".format(i) + "-{}".format(j) + ".xls" print(url) if i > 9: if i > 9 or j < 8: url = "https://Here is a

问题 I want to block access to urls that have excess characters at its end. E.g. I want nginx to block requests to https://www.example.com/url-pattern/amp/extra-chars/more-extra but want it to allow https://www.example.com/url-pattern/amp or https://www.example.com/url-pattern/amp/ Will this work? location .*\/amp\/. { deny all } Please guide. 回答1: Solved it myself. If anyone is looking for the same solution location ~* /amp/. { deny all; } 来源： https://stackoverflow.com/questions/62984495/regex-to

问题 I've attempted the solution in the following. Inserting an Online Picture to Excel with VBA Unfortunately I get a run-time error '1004' "Unable to get the Insert property of the Picture class" which stops on the following code : Set myPicture = ActiveSheet.Pictures.Insert(pic) Could this be due to my Office version 2016 (64bit) ? If not, are there any suggestions of how I might get embed images to adjacent cells in column AK using the image urls from column AJ ? Thanks in advance 回答1: There's

问题 I am trying to get the URL of the following get request; String url = ['url_here']; Future<Post> fetchPost() async { final response = await http.get(url); if (response.statusCode == 200) { return Post.fromJson(json.decode(response.body)); } else { throw Exception('Failed to load post'); } } I get a statuscode of 200. Any ideas? To clarify, When you enter the url in a browser it brings me to a page with a url that has a code in it. I am trying to extract that code. 回答1: followRedirects is true

问题 I have multiple Geoserver layers, let 3 here (Rainfall, Maximum Temperature and Minimum Temperature) The name of layer and values assigned in the radio button to switch the layers is same. As I check the radio button, I am getting the value of that specific layer but when I pass this value, I am unable to fetch the URL of that layer how to make this layer value string work in GetFeatureInfo function of Openlayers 6, to get the URL of that specific layer which we select from sidebar? Any other

问题 The commonly accepted file format for a .url file (internet shortcut) is as follows: [InternetShortcut] URL=http://example.com WorkingDirectory=C:\WINDOWS\ ShowCommand=7 IconIndex=1 IconFile=C:\WINDOWS\SYSTEM\url.dll Modified=20F06BA06D07BD014D HotKey=1601 Is there a way, most likely a hack, to make a single internet shortcut file open up multiple tabs? I tried this: ... URL=http://example.com URL=http://example.com ... and this: ... URL=http://example.com; http://example.com ... and the same

问题 Say we have the following urls: 1. http://example.com#hash0 2. http://example.com#hash0#hash1 3. http://example.com#hash0/sample.net/ 4. http://example.com#hash0/sample.net/#hash1 5. http://example.com#hash0/image.jpg 6. http://example.com#hash0/image.jpg#hash1 7. something.php#?type=abc&id=123 8. something.php#?type=abc&id=123#hash0 9. something.php/?type=abc&id=#123 .................................... and more permutations of this kind, you got the point. How can I selectively remove the

问题 I have a wordpress platform and I am looking at displaying variable content on a page based on a variable in the url. I have a 1 page website (www.vidlab.io) and i would like the section "GoPro Video Editing" to display information about GoPro video editing if the url is vidlab.io/?type=GoPro or information about wedding editing if the Url is vidlab.io/?type=wedding, and so on. I have read that you can use a get call, but not really sure how to have that information in the URL without getting

问题 Is somebody aware of how to pass multiple urls in one request to the Wayback Machine API ? Or is it even possible to do that? I looked for it all over the internet but I didn't find anything about how to do it. 回答1: one url, one request, one answer - but a list of urls can be checked within the loop; for ex. in R: urls <- c("http://onet.pl","http://wired.com","http://geocities.com") ask_wm_api <- function(urls) { library(jsonlite) df <- data.frame() for(u in urls) { x <- fromJSON(paste0("http